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anygoal [31]
3 years ago
11

What list did poe appear on for the search engine lycos?

Computers and Technology
1 answer:
HACTEHA [7]3 years ago
4 0
What list did Poe appear on for the search engine Lycos"
Millines most wanted number four. Edgar Allan Poe was born on January 19, 1809, in Boston, Massachusetts. His father, named David Poe Jr and his mother, named Elizabeth Arnold Hopkins Poe, were touring actors. 
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What are some advantages to having ads tailored to your data?
laiz [17]

Answer:

That you will find something, that you need or just something you find useful. And something that might take your interest.

6 0
2 years ago
¿Es lo mismo hablar de tecnología que de computadora?
V125BC [204]

Translation:  

Is it the same to talk about technology as about the computer?

5 0
3 years ago
Can some one fix this <br> input ("Enter a number: ") <br> print (num * 8)
Kaylis [27]
If you save the input as num,
this will print the input 8 times.

num = input("Enter a number: ")
print(num * 8)

If you want to do actual math calculations,
then the input needs to be a number.

num = float(input("Enter a number: "))
print(num * 8)

This doesn't account for any errors in which the user doesn't input a number, but I don't think that's what you were looking for anyway :)
6 0
3 years ago
Write a program whose input is a character and a string, and whose output indicates the number of times the character appears in
Zina [86]

Answer:

Here is the C++ program:

#include <iostream> // to include input output functions

using namespace std; // to identify objects like cin cout

int counter(string userString, char character) { //function counter

   int count = 0;   // counts the no of times a character appears in the string

   for (int i=0;i<userString.length();i++)  

// loop to move through the string to find the occurrence of the character

       if (userString[i] == character) //if characters is found in the string

           count++;   //counts the occurrence of the character in the string

   return count; }   //returns the no of times character occurs in the string

int main() { //start of the main() function body

   string s; // stores the string entered by the user

   cout<<"Enter a string: "; //prompts user to enter the string

   cin>>s; //reads the string from user

   char ch; //stores the character entered by the user

   cout<<"Enter a character: "; //prompts user to enter a character

   cin>>ch; //reads the character from user

   cout << counter(s, ch) << endl; }  

//calls counter function to find the number of times a character occurs in the //string

Explanation:

The counter function works as following:

It has a count variable which stores the number of occurrences of a character in the userString.

It uses a for loop which loops through the entire string.

It has i position variable which starts with the first character of the string and checks if the first character of userString matches with the required character.

If it matches the character then count variable counts the first occurrence of the character and in the userString and is incremented to 1.

If the character does not match with the first character of the userString then the loops keeps traversing through the userString until the end of the userString is reached which is specified by the length() function which returns the length of the string.

After the loop ends the return count statement is used to return the number of occurrences of the character in the userString.

The main() function prompts the user to enter a string and a character. It then calls counter() function passing string s and character ch arguments to it in order to get the number of times ch appears in s.

The output is attached in a screenshot.

6 0
4 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
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