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Vadim26 [7]
3 years ago
6

Please help quickly −2/9−(−1/3÷3/5)

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

0.33333333333

Step-by-step explanation:

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The answer is E 17 you divide 84 by 5
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Mr. Mole left his burrow and started digging his way down at a constant rate. Time (minutes) Altitude (meters) 666 -20.4−20.4min
Juli2301 [7.4K]

Answer:

-6 meters.

Step-by-step explanation:

We have been given Mr. Mole left his burrow and started digging his way down at a constant rate.

We are also given a table of data as:

Time (minutes)     Altitude (meters)

6                                   -20.4

9                                   -27.6

12                                   -34.8

First of all, we will find Mr. Mole's digging rate using slope formula and given information as:

m=\frac{y_2-y_1}{x_2-x_1}, where,

y_2-y_1 represents difference of two y-coordinates,

x_2-x_1 represents difference of two corresponding x-coordinates of y-coordinates.

Let (6,-20.4) be (x_1,y_1) and (9,-27.6) be (x_2,y_2).

m=\frac{-27.6-(-20.4)}{9-6}

m=\frac{-27.6+20.4}{3}

m=\frac{-7.2}{3}

m=-2.4

Now, we will use slope-intercept form of equation to find altitude of Mr. Mole's burrow.

y=mx+b, where,

m = Slope,

b = The initial value or the y-intercept.

Upon substituting m=-2.4 and coordinates of point (6,-20.4), we will get:

-20.4=-2.4(6)+b

-20.4=-14.4+b

-20.4+14.4=-14.4+14.4+b

-6=b

Since in our given case y-intercept represents the altitude of Mr. Mole's burrow, therefore, the altitude of Mr. Mole's burrow is -6 meters.

6 0
3 years ago
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Analyze the scatterplot below, what prediction can you make about the group of students used in the study from the graph below?
SCORPION-xisa [38]

Answer:

i do not understand

Step-by-step explanation:

8 0
3 years ago
Cos(sin^-1(24/26)<br> Use a sketch to find the exact value of the following expression
creativ13 [48]
Hello,

Let y=sin^(-1)(12/13.
==>sin y=12/13
==>cos y=√(1-(12/13)²)=√(25/169)=5/13

Answer 5/13

4 0
3 years ago
What is the percentage… b of sugar in the syrup made of 10 kg of water and 4 kg of sugar?
Artist 52 [7]

Answer:

<h3>28 4/7 % ≈ 29%</h3>

Step-by-step explanation:

4 kg - weight of sugar

10 kg - mass of water

4kg + 10kg = 14kg - weight of the syrup

\dfrac{4kg}{14kg}=\dfrac{2}{7}

The sugar is 2/7 of the weight of the syrup.

Convert to the percentage:

\dfrac{2}{7}=\dfrac{2}{7}\cdot100\%=\dfrac{200}{7}\%=28\dfrac{4}{7}\%\aaprox29\%

6 0
3 years ago
Read 2 more answers
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