Need to find:
- Perimeter of new square formed?

Solution:
- Side of smaller square = 3cm.
- Side of Bigger square = 9cm

Using formula:
- Perimeter of square = 4 × side

<u>Perimeter of smaller </u><u>square:</u>
⟹ 4 × 3
⟹ 12 cm

<u>Perimeter of Bigger square:</u>
⟹ 4 × 9
⟹ 36cm

Perimeter of new square = Perimeter of Bigger square - Perimeter of smaller square
⟹ 36 - 12
⟹ 24 cm

∴ Perimeter of new square formed is 24 cm.

Use the rational zero theorem
In rational zero theorem, the rational zeros of the form +-p/q
where p is the factors of constant
and q is the factors of leading coefficient

In our f(x), constant is 2 and leading coefficient is 14
Factors of 2 are 1, 2
Factors of 14 are 1,2, 7, 14
Rational zeros of the form +-p/q are

Now we separate the factors


We ignore the zeros that are repeating

Option A is correct



first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!
since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!
Answer:

Step-by-step explanation:
The first step is to find the GCF. Here, it's 3.

Then, you factor the polynomial in the parenthesis.
To find the factors, you will need to find 2 numbers that add to -7, and multiply to 10. -2 and -5 add to -7 and multiply to 10. Now, replace -7a with the factors.

This of this polynomial as 2 problems.

Then, factor again.


Then, you keep the factors in parenthesis, and combine the numbers on the outside.

Since, there are 2 of the same factor, you only need one.

BUT REMEMBER!! In the very beginning, we had a 3 that we took out, we STILL need to add that to the final answer. The <u>final answer</u> is:

Answer:
Oakdale
Step-by-step explanation:
The median can be seen inside the rectangle in the box-and whisker plot. It is the point in the middle, cutting the rectangle in two. Looking at the plots, Oakdale has a lower median.