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3 years ago

Will some smart people help me out? :) 20 points

Mathematics

2 answers:

Contact [7]3 years ago

6 0

Answer:

V≈1670.81

Step-by-step explanation:

babymother [125]3 years ago

4 0

Answer:

22.3

Step-by-step explanation:

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A car can travel 300 miles in the same amount of time it takes a bus to travel 180 miles. if the rate of the bus is 20 miles per

Gnesinka [82]

It would be the bus goes 75 miles per hour while the car is going 95 miles per hour

6 0

2 years ago

What’s the value for 2.3 + 4.09 =n

Rashid [163]

Answer:

n = 6.39

Explanation:

2.3 + 4.09 = n
6.39 = n

Swap the sides of the equation
n = 6.39

6 0

2 years ago

Help on this plzz on this last one plzz

kozerog [31]

(6x-18)(x+4)/(3x-9)=6(x-3)(x+4)/3(x-3)=2(x+4)=2x+8

7 0

3 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

2 years ago

Help please!!!!!!!!!!!

kvasek [131]

Answer:

B. 2/3

Step-by-step explanation:

To solve this we have to take into account this axioms:

- The total probability is always equal to 1.

- The probability of a randomly selected point being inside the circle is equal to one minus the probability of being outside the circle.

Then, if the probabilities are proportional to the area, we have 1/3 probability of selecting a point inside a circle and (1-1/3)=2/3 probability of selecting a point that is outside the circle.

Then, the probabilty that a random selected point inside the square (the total probability space) and outside the circle is 2/3.

3 0

3 years ago