Question

Consider the quadratic function f(x)= 9x^2+30x+25=0

Answer 1

Answer:

D) 0

There is 1 real solution.

Step-by-step explanation:

Hi there!

$f(x)= 9x^2+30x+25=0$

This is written in standard form:

$f(x)=ax^2+bx+c$

This means:

a=9

b=30

c=25

The discriminant states:

$D=b^2-4ac$

If D>0, there are 2 real solutions.

If D=0, there is 1 real solution.

If D<0, there are 2 complex solutions.

Plug in the values:

$D=30^2-4(9)(25)\\D=0$

Therefore, there is 1 real solution.

I hope this helps!