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Luden [163]
2 years ago
5

Consider the quadratic function f(x)= 9x^2+30x+25=0

Mathematics
1 answer:
Alchen [17]2 years ago
4 0

Answer:

D) 0

There is 1 real solution.

Step-by-step explanation:

Hi there!

f(x)= 9x^2+30x+25=0

This is written in standard form:

f(x)=ax^2+bx+c

This means:

a=9

b=30

c=25

The discriminant states:

D=b^2-4ac

If D>0, there are 2 real solutions.

If D=0, there is 1 real solution.

If D<0, there are 2 complex solutions.

Plug in the values:

D=30^2-4(9)(25)\\D=0

Therefore, there is 1 real solution.

I hope this helps!

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