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2 years ago

Solve for n. 2n − 35=52n − 35=5

Mathematics

2 answers:

melomori [17]2 years ago

7 0

The answer is n= 35/2

olga_2 [115]2 years ago

4 0

Answer:

The value of n in the given equation is 20.

Step-by-step explanation:

Given equation is,

$2n-35=5$

Add 35 on both sides, ( additive property of equality )

$2n=5+35$

$2n=40$

Divide both sides by 2, ( division property of equality )

$n=20$

Hence, the value of n in the given equation is 20.

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What is the answer to -6(a+8)

Dafna11 [192]

Answer: -6a-48

Step-by-step explanation:

First -6 goes into a and that turns into -6a and then -6 goes into 8 and that turns into -48 so ur answer would be: -6a-48

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3 years ago

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

Do Now

Finger [1]

Answer:

17, 558 employees

Step-by-step explanation:

Altogether = 70,010 employees , First location = 34, 857 employees, second location = 17, 595 employees, Third location = ?

Let the number of employees in the third location be x

70,010 + 17, 595 + x = 70,010

x = 70, 010 - 52452

x = 17, 558( Answer)

17, 558 employees work in the third location

3 0

3 years ago

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AnnZ [28]

Answer:

-16

Step-by-step explanation:

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3 0

3 years ago

Find the sum and product of the roots.

xz_007 [3.2K]

Answer:

sum= -3 product=-4

Step-by-step explanation:

2x^2-2x+8x-8

2x(x-1)+8(x-1)

(2x+8)(x-1)

x=-4 x=1

8 0

3 years ago

Read 2 more answers