We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>
</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in
the answer is
4.23 in
Based on the dimensions of the basketball court, we can calculate that the area of the scaled copy is<u> 18 ²³/₆₄ feet².</u>
<h3>Dimensions of scaled copy</h3>
Every 16 feet of the actual court is 1 foot on the scaled copy. The dimensions of the scaled copy are therefore:
= 94 / 16 = 50 / 16
= 5.875 feet = 3.125 feet
<h3>Area of scaled copy </h3>
= Length x Width
= 5.875 x 3.125
= 18.359375
= 18 ²³/₆₄ feet²
In conclusion, the area is 18 ²³/₆₄ feet².
Find out more on area at brainly.com/question/25292087.
Answer:
Step-by-step explanation:
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Answer:
4x²+12xy+9y²
(2x+3y)²
=(2x+3y)*(2x+3y)
2x *2x , 2x *3y , 3y* 2x ,3y* 3y
=4x²+12xy+9y²
