To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- <span>The diameter of a basketball rim is 18 inches. - A standard basketball has a circumference of 30 inches.
2. Therefore, the diameter of the standard basketball is:
D=30 inches/</span>π D=9.54 inches
3. Therefore you have:
(18 inches-9.54 inches)=8.45 inches on both sides
4. Then, the distance <span>the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim, is: </span> d=8.45 inches/2 d=4.22 inches
We know that circumference=2*pi*r-------> r=circumference/(2*pi) circumference=30 in r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in the radius of a <span>standard basketball is 4.77 in </span> <span>the distance between the ball and the rim is equal to </span>radius of a basketball rim minus radius of a a standard basketball radius of a basketball rim =18/2------> 9 in radius of a a standard basketball=4.77 in<span>
</span> the distance between the ball and the rim=[9-4.77]------> 4.23 in
Since you want to use the SAS theorem, you must find sides that are either side of angles BAC and DAE. You have already made use of sides AE and AC, so the other sides you need to choose are AB and AD. The appropriate relationship for similarity is ...
... AD = 2AB
since you want the sides of triangle ADE to be twice then length of those in triangle ABC.
