To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- <span>The diameter of a basketball rim is 18 inches. - A standard basketball has a circumference of 30 inches.
2. Therefore, the diameter of the standard basketball is:
D=30 inches/</span>π D=9.54 inches
3. Therefore you have:
(18 inches-9.54 inches)=8.45 inches on both sides
4. Then, the distance <span>the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim, is: </span> d=8.45 inches/2 d=4.22 inches
We know that circumference=2*pi*r-------> r=circumference/(2*pi) circumference=30 in r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in the radius of a <span>standard basketball is 4.77 in </span> <span>the distance between the ball and the rim is equal to </span>radius of a basketball rim minus radius of a a standard basketball radius of a basketball rim =18/2------> 9 in radius of a a standard basketball=4.77 in<span>
</span> the distance between the ball and the rim=[9-4.77]------> 4.23 in
