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irina1246 [14]
3 years ago
10

Please help me with this question asap i’ll give you brainliest

Mathematics
2 answers:
Alja [10]3 years ago
5 0

Answer:

\Huge \boxed{500^{\frac{1}{3} }}

Step-by-step explanation:

Applying rule : \displaystyle \sqrt[n]{x} =x^{\frac{1}{n} }

\displaystyle \sqrt[3]{500} =500^{\frac{1}{3} }

mina [271]3 years ago
4 0

Answer:

C

Step-by-step explanation:

Recall the exponent property that:

x^{\frac{1}{n}}=\sqrt[n]{x}

And vice versa:

\sqrt[n]{x}=x^{\frac{1}{n}}

Thus:

\sqrt[3]{500} =(500)^{\frac{1}{3}}

The answer is C

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8 0
4 years ago
Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni
Serjik [45]

Answer:

x =12\ or\ -8

Step-by-step explanation:

Given

(x_1,y_1) = (6,5)

(x_2,y_2) = (8,2)

(x_3,y_3) = (x,11)

Area = 15

Required

Find x

The area is calculated as thus:

Area = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|

Substitute values

15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|

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15 = \frac{1}{2}|-54 + 48 + 3x|

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Multiply through by 2

2 * 15 = \frac{1}{2}|-6 + 3x| * 2

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Remove absolute sign

30 = -6 + 3x\ or\ -30 = -6 + 3x

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Divide by 3

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<em>So, the coordinates are (-8, 11) or (12,11)</em>

3 0
3 years ago
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