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Lapatulllka [165]

2 years ago

9

quadrilateral kstu has vertices at (7,0) (4,-6) (0,-2) and (0,0). rotate 180 degrees around the origin

1 answer:

solong [7]2 years ago

5 0

Step-by-step explanation:

so basically for this on u have to draw this on graph every first number of the coordinate is on x axis e.g . (7,0) 7 is on x axis and 0 is on Y axis. you can use tracing paper for this which will be more helpful as u can trace the shape and move it half way.

As u rotate it around the origin so u just turn it half way. eg I drawn it on the picture.

hope this make sense :)

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Suppose two events A and B are mutually exclusive, with P(A) ≠ 0 and P(B) ≠ 0. By working through the following steps, you'll se

DanielleElmas [232]

Answer with Step-by-step explanation:

We are given that two events A and B are mutually exclusive.

$A\cap B=\phi$

$P(A\cap B)=0$

$P(A)\neq 0$

$P(B)\neq 0$

a.For mutually exclusive events,

$P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(A)}=0$

Therefore, event A can not occurred if event B has occurred because two events can not occur together.

Answer:No, by definition mutually exclusive events cannot occur together.

b.When two events are independent

Then , $P(A\cap B)=P(A)\cdot P(B)$

$P(A/B)=\frac{P(A)\cdot P(B)}{P(B)}=P(A)$

If two events are mutually exclusive then

$P(A\cap B)=0$

Then , $P(A/B)=0$

Therefore, $P(A/B)\neq P(A)$

Hence, we can concluded that events A and B are not independent if they are mutually exclusive.

Answer:Yes, $P(A/B)\neq P(A)$

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