quadrilateral kstu has vertices at (7,0) (4,-6) (0,-2) and (0,0). rotate 180 degrees around the origin
1 answer:
Step-by-step explanation:
so basically for this on u have to draw this on graph every first number of the coordinate is on x axis e.g . (7,0) 7 is on x axis and 0 is on Y axis. you can use tracing paper for this which will be more helpful as u can trace the shape and move it half way.
As u rotate it around the origin so u just turn it half way. eg I drawn it on the picture.
hope this make sense :)
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By graphing the given points, we will get the attached figure
which represents:
f(x) = 3 sin x
but sin x = cos (x - π/2)
∴ f(x) = 3 cos ( x - π/2 )
The correct choice is option ⇒⇒⇒ <span>f(x) = 3 cos(x − pi over 2 ) </span>
which represents:
f(x) = 3 sin x
but sin x = cos (x - π/2)
∴ f(x) = 3 cos ( x - π/2 )
The correct choice is option ⇒⇒⇒ <span>f(x) = 3 cos(x − pi over 2 ) </span>