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Anna35 [415]
3 years ago
7

In attachment, help please 1 QUESTION, BRAINLIEST GETS 20 PTS

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
8 0
The answer is:   0.00000146  .
______________________________________________________
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The table represents the function 7 = 5x- Output ) Input (3) -2 -18 8 x 1 2 2 12 8 2 2. What is the input when the output is 12
notsponge [240]
y_{-2}=5\cdot(-2)-8=-10-8=-18y=5x-812=5x-812+8=5x20=5xx=\frac{20}{5}x=4

6 0
1 year ago
The terminal velocity of a person falling through air is about 100Km/hr. The acceleration due to gravity is 10ms−2. Use this inf
Aleonysh [2.5K]

The question here is how long does it take for a falling person to reach the 90% of this terminal velocity. The computation is:

The terminal velocity vt fulfills v'=0. Therefore vt=g/c, and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the differential equation shows that the time needed to reach velocity v is 

t= ln [g / (g-c*v)] / c. 

With v=.9 vt =.9 g/c,

t = ln [10] /c = 6.4 sec.

8 0
3 years ago
Select the correct answer.<br> What are the solutions of this quadratic equation?<br> 25x^2 + 1 = 0
Llana [10]

Answer:

no solution because the square root of a negative number is not a real number d=-100

4 0
2 years ago
Talk to me /:<br> pleases
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5

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2 years ago
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At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
2 years ago
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