The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
no solution because the square root of a negative number is not a real number d=-100
Answer:
5
Step-by-step explanation:
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Answer:
1092
Step-by-step explanation:
We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function
. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.
We will use average rate of change formula to solve our given problem.

Upon substituting our given values, we will get:






Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.