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snow_tiger [21]
4 years ago
15

A. (1, 4) B. (-2, -3) C. ( -3, 5) D. (0,4)

Mathematics
1 answer:
snow_lady [41]4 years ago
5 0
C because 5 is greater than -2 and -3+5 is 2 which is less than 4
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Fill in the blank to show an example of the symmetric property: <br>If JK = ST, then _ = __ ​
sweet [91]
The answer would be ST=JK
6 0
3 years ago
2x+ 3 / 5= y<br> rearrange to make x the subject
Elza [17]

Answer:

<h3>(5y-3)/2</h3>

Step-by-step explanation:

Given the equation 2x+ 3 / 5= y

Cross multiply

2x+3 = 5 * y

2x+3 = 5y

Subtract 3 from both sides

2x+3-3 = 5y - 3

2x = 5y-3

Divide both sides by 2

2x/2 = (5y-3)/2

x = (5y-3)/2

Hence the value of x is (5y-3)/2

4 0
3 years ago
The half-life is a substance is 375 years. If 70 grams is present now, how much will be present in 500 years?
Lynna [10]

Answer:

27.76 grams will be present in 500 years

Step-by-step explanation:

The given formula is A=A_{o}e^{kt} , where A is the value of the substance in t years, and A_{o} is the initial value

∵ The half-life is a substance is 375 years

- Substitute A by \frac{1}{2}A_{o} and t by 375 to find the value of k

∴ \frac{1}{2}A_{o}=A_{o}e^{375k}

- Divide both sides by A_{o}

∴ \frac{1}{2}=e^{375k}

- Insert ㏑ in both sides

∴ ㏑( \frac{1}{2} ) = ㏑ ( e^{375k} )

- Remember ㏑ ( e^{n} ) = n

∵ ㏑ ( e^{375k} ) = 375 k

∴ ㏑( \frac{1}{2} ) = 375 k

- Divide both sides by 375

∴ k ≈ -0.00185

∴  A=A_{o}e^{-0.00185t}

∵ 70 grams is present now

- That means the initial value is 70 grams

∴ A_{o} = 70

∵ The time is 500 years

∴ t = 500

- Substitute the values of A_{o} and t in the formula

∵ A=70e^{-0.00185(500)}

∴ A = 27.76

∴ 27.76 grams will be present in 500 years

3 0
3 years ago
Can someone help with this please.<br><br>​
sergeinik [125]
Simplified
2/5x-5-1/3
2 x -5 - 1/3
5
​-10/5 - 1/3
-2 - 1/3
-7/3
4 0
4 years ago
Read 2 more answers
Help ASAP please ill mark brainliest
yKpoI14uk [10]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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