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dolphi86 [110]
3 years ago
5

Is "10 times as much" a moderate or large difference?

Mathematics
2 answers:
Yanka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

large. if my friend has 10 dollars, and i have 10 times as much, i have 100 dollars. so yes, it is large

natulia [17]3 years ago
3 0

Answer:

large

Step-by-step explanation:

its getting multiplied

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Find the z-score such that the area under the standard normal curve to the left is 0.79.
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Answer:

1

Step-by-step explanation:

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3 years ago
22.5 + 7(n−3.4) simplified
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-1.3+7n is the answer
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Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
Factor completely x3 − 2x2 − 8x 16. (x 2)(x2 8) (x − 2)(x2 8) (x 2)(x2 − 8) (x − 2)(x2 − 8).
dybincka [34]

Answer:

D) (x - 2)(x² - 8)

Step-by-step explanation:

Separate the polynomial into two groups of two terms and factor out the common value from each group.  If the values factored out from each group are the same, then you can use the grouping method.  The factors will be the outside terms and the common factor.

   x³ - 2x²     +     -8x + 16

=  x²(x - 2)      +     -8(x - 2)

= (x² - 8)(x - 2)

8 0
2 years ago
It's moving day, and Lydia has packed her books into large and small boxes. The large boxes hold 35 books, and the small ones ho
Virty [35]

The number of large boxes is 4 and the number of small boxes is 14.

<u><em>Explanation</em></u>

Suppose, the number of large boxes is x and the number of small boxes is y

As, the total number of boxes is 18, so the first equation is....

x+y= 18 .......................................(1)

The large boxes hold 35 books, and the small ones hold 20 books and the total number of books is 420. So the second equation will be .....

35x+20y=420................................(2)

Now solving equation (1) for y itself , we will get....

y= 18-x

We will plug this y= 18-x into equation (2). So.....

35x+20(18-x)=420\\ \\ 35x+360-20x=420\\ \\ 15x= 420-360\\ \\ 15x=60\\ \\ x= \frac{60}{15}=4

Now plugging this x=4 into the equation y= 18-x.......

y= 18-4= 14

Thus, the number of large boxes is 4 and the number of small boxes is 14.

3 0
2 years ago
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