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Diano4ka-milaya [45]
3 years ago
14

When conducting legal experiments on animals a researcher needs to obtain consent from the?

Biology
1 answer:
Alenkasestr [34]3 years ago
7 0
When conducting legal experiments on animals, a researcher needs to obtain consent from the INSTITUTIONAL RESEARCH BOARD.
Each research institution has research board which sees into uses of animals for research purposes, consent must be obtained from the board before experiments involving usage of animals is carried out.

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The peptidoglycan cell wall of bacteria is most analogous to _____.
belka [17]

Answer: chain link fence

Peptidoglycan could be found in high number on gram positive cell walls. The structure of peptidoglycan looks like a cross link which makes it sturdy, so rain coat would be false. It is not an impenetrable brick wall because it still allow some ion and food pass through it.  Sugar candy coat sounds good but chain link fence would be better.

8 0
3 years ago
After the cerebellum receives proprioceptive information from muscles carrying out a voluntary movement, where does it send corr
Pani-rosa [81]

After the cerebellum receives proprioceptive information from muscles carrying out a voluntary movement, where does it send corrective feedback to primary motor cortex and cerebral nuclei.

The cerebellum, also known as the corticocerebellum, has a close connection to the regulation of movement timing, rate, range, length, direction, and strength. The cerebellum receives information from the command neurons and also obtains feedback (afferent) from the proprioceptive terminals of the muscles, tendons and joints regarding what the actual movements produce .

All these information are combined and the correction signals are given to the motor cortex. The motor nuclei of the cranial nerves and spinal cord exert the lowest level of motor control. Through the closed feedback loop, this occurs.

Learn more about cerebellum here:

brainly.com/question/13504830

#SPJ1

5 0
1 year ago
Hey guys...........please help me with this one❤❤❤❤ Every organism needs food. Does a cell also need it? Explain very briefly.
Alexxx [7]

Cells do need food. In a process known as cellular respiration, cells convert biochemical energy (oxygen as food) from nutrients into adenosine triphosphate (ATP), and then release waste products.


hope this helps.. :D

3 0
4 years ago
Duchene muscular dystrophy, or DMD, is a recessive, x-linked disease. What would you expect to see in the offspring of a woman w
Harman [31]

It is expected to see in the offspring of a woman who has DMD and a man who does not have the disease that all of their sons and none of their daughters will have the disease

Option A.

<h3><u>Explanation:</u></h3>

Duchene muscular dystrophy, also known as DMD is a recessive, x-linked disease. It occurs when there is a mutation in the dystrophin gene. This mutation further affects the muscles of the body leading it to degenerate and ultimately death.

When a woman with DMD and a man without DMD have an offspring, their daughters and the sons will get the mutated gene signature from the mother as she is the carrier. But since the father has normal genes, the daughters will become the carriers and will not be afflicted by it. This is because the normal X chromosome from the father will be passed on to them. The sons on the other hand will have the disease as they will get one of their mother's X chromosome which would be carrying the mutated gene.

5 0
3 years ago
In cocker spaniels, black color (b) is dominant over red (b), and solid color (S) is dominant over spotted (s).
Levart [38]

Answer:

<h2>e) 3/4 </h2>

Explanation:

As given;

Black (B) is dominant over red (b), so B is dominant over b.

Solid (S) is dominant over spotted color(s), so S is dominant over s.

Offspring of BBss and bbss individuals are:

Gametes of parent BBss are Bs, Bs and gamete of bbss are bs, bs

offspring are : all Bbss

Cross between these offspring is; Bbss×Bbss

Gametes of parent Bbss are: Bs and bs  as given that the genes are linked.

Bs, bs × Bb, bs

Offspring are = BBss, Bbss, Bbss, bbss

Black spotted (B_ss) = 3/4

3 0
3 years ago
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