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puteri [66]
2 years ago
12

In cats the allele for short hair is dominant over the allele for long hair. A short haired male and long haired female have kit

tens. Eight kittens have short hair and 3 have long hair. A) What are genotypes of the parents? B) What is the expected ratio of short to long haired cats? C) What Is the actual ratio in this problem?
Biology
1 answer:
SCORPION-xisa [38]2 years ago
4 0

Answer:

Genotype of parents:                  Ss     x     ss

Genotype of offsprings:                  Ss    ss

Expected ratio of short to long:      2  :   2 = 1 :  1

The actual ratio in this problem is Eight kittens have short hair and 3 have long hair: 8 : 3

Explanation:

In cats the allele for short hair is dominant over the allele for long hair. (SS or Ss for short hair; ss for long hair).

A short haired male and long haired female have kittens. Eight kittens have short hair and 3 have long hair.

For the parents to have been able to produce long haired offsprings, it means both parents possess one copy each of the recessive traits. Thus we have

Phenotype of parent: A short haired male and long haired female

Genotype of parents:                  Ss     x     ss

Genotype of offsprings:                  Ss    ss

Expected ratio of short to long:      2  :   2 = 1 :  1

The actual ratio in this problem is Eight kittens have short hair and 3 have long hair: 8 : 3

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In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant
Ivenika [448]

Answer and Explanation:

<em><u>Available data</u></em>:

  • Comb shape is determined by genes at two loci (R, r and P, p).
  • The walnut comb genotype is R_P_.
  • The rose comb genotype is R_pp.
  • The pea comb genotype is rrP_.
  • The single genotype is rrpp.

a. <em>Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring: </em>

Parental)             RrPp       x          rrpp

Gametes)   RP   Rp   rP   rp     rp   rp   rp   rp

Punnet Square)      RP       Rp     rP        rp

                     rp   <em>RrPp    Rrpp   rrPp   rrpp</em>

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. <em>Rose crossed with pea produces 20 walnut offspring</em>.

Parental)              RRpp       x          rrPP

Gametes)   Rp   Rp   Rp   Rp     rP   rP   rP   rP

Punnet Square)      Rp       Rp     Rp        Rp

                     rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp  RrPp

                    rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp   RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. <em>Pea crossed with single produces 1 single offspring</em>.

This is not possible, because the pea genotype involves <u>at least</u> one dominant allele P. There are two possible crosses: <em>rrPp x rrpp</em>, which must produce half of the progeny pea and the other half single, or <em>rrPP x rrpp</em> which produce a whole pea progeny with no single offspring.  

Parental)              rrPp       x          rrpp

Gametes)   rP   rp   rP   rp     rp   rp   rp   rp

Punnet Square)     rP       rp       rP      rp

                     rp   <em>rrPp    rrpp   rrPp   rrpp</em>

                    rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. <em>Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring</em>.

This is not possible, because having one of the parents with a rose phenotype  involves <u>at least one R allele</u>, which means that <u>there must be rose phenotype</u> in the progeny.

Parental)             Rrpp       x          rrPp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)     Rp       Rp       rp      rp

                     rP  <em> RrPp </em>   RrPp  <em> rrPp</em>   rrPp

                     rP   RrPp    RrPp   rrPp   rrPp

                     rp    <em>Rrpp</em>    Rrpp   <em>rrpp </em>  rrpp

                     rp   Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. <em>Rose crossed with single produces 31 rose offspring</em>.

Parental)              RRpp       x          rrpp

Gametes)   Rp   Rp   Rp   Rp     rp   rp   rp   rp

Punnet Square)     Rp       Rp       Rp      Rp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. <em>Rose crossed with single produces 10 rose and 11 single offspring.</em>

Parental)              Rrpp       x          rrpp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)      Rp       Rp       rp      rp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0
3 years ago
Anyone good at Biology could you give me a helping hand please!
andriy [413]
1. Anaphase. In <span>Anaphase the sister chromatids separate from each other to the opposite sides of the cells.

2. </span>Chromosomes would not separate into two nuclei. <span>Mitosis is a process cell division, where one cell divides into two identical cells.
</span>
3. Metaphase I. <span>Meiosis prophase I is the phase in which chromosomal crossing over occurs. The phase after prophase I is metaphase I.

4. </span>Its body cells would have 36 chromosomes, and its gametes would have 18 chromosomes. <span>In the gametes, there are half of the number of chromosomes present in the body cell.

5. </span><span>A species has to adjust rapidly to a changing environment. To adjust to the environment, crossing over is necessary, and it does not occur in mitosis, but meiosis.

6. 50 percent. 
Parents:          Yy      x     yy
Offspring:    Yy    Yy    yy   yy
50 % is Yy  and 50% is yy.

7. </span><span>One parent had white eyes and the other was heterozygous for eye color. The ratio in the offspring is 50-50. The only possibility is the following:
Parents:       Rr     x     rr
Offspring   Rr    Rr   Rr   Rr

8. </span><span>Their fur will be a mixture of red and white hairs. The offspring will be heterozygous. They will have alleles for both red and white hairs and both will be expressed.
</span>
9. Not enough information.

10. <span>Both of the parents' genotype must have been Pp. The genotype of the white plant is pp since it is recessive:
Parents:        Pp     x     Pp
Offspring:   PP   Pp   Pp   pp
One of the four is white.</span>

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