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3 years ago

0.21 simplified as a fraction?

Mathematics

2 answers:

ra1l [238]3 years ago

4 0

You move decimal point 2 places to the right
21/100
this cannot be simplified further

ivann1987 [24]3 years ago

4 0

That would be 21/100 but 21/100 cannot be simplified because they do not have a number in common. example:2/4 can be simplified because 2/4 divided by 2 would= 1/2 because 2 goes into 2, 1 time and 2 goes into 4, 2 times

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35 POINTS! PLEASE HELP MEEE!!! HURRY PLEASE IM RUNNING OUT OF TIME!!!!!!!!!!!!!!!!!

lesantik [10]

Answer:

<h2>CYLINDER</h2>

Surface Area = 471.2 cm^2

<h2>TRIANGULAR PRISM</h2>

Surface Area = 60.75 m^2

Step-by-step explanation:

<h2>CYLINDER</h2>

The surface area formula for a cylinder is π x diameter x (diameter / 2 + height), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius x 2 x (radius + height). ( π =3.14 )

FORMULA:

π x 5 x 2 x 15

WORK:

π x 5 = 15.7

15.7 x 2 = 31.4

31.4 x 15 = 471

<h2>TRIANGULAR PRISM</h2>

The surface area formula for a triangular prism is 2 * (height x base / 2) + length x width1 + length x width2 + length x base.

FORMULA:

2 x (2.5 x 1.5/2) + (6 x 4) + (6 x 4) + (6 x 1.5)

WORK:

(2.5 x 1.5) = 3.75/2 = 1.875

1.875 x 2 = 3.75

(6 x 4) = 24

(6 x 1.5) = 9

3.75 + 24 + 24 + 9 = 60.75

5 0

3 years ago

Read 2 more answers

Which of the following is an equivalent expression to: -2(-5x - 8)

exis [7]

Answer:

10x + 16

Step-by-step explanation:

Doing the distributive property, we get the answer 10x + 16.

5 0

2 years ago

Read 2 more answers

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$