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Dima020 [189]
3 years ago
14

Given figure LMNO ~ figure STUV, what is the value of x? LMNO has 4.1 in and 22. in and STUV has 12.3 in

Mathematics
2 answers:
Furkat [3]3 years ago
7 0
Set up a proportion:

4.1/22 = 12.3/x

Cross multiply:

4.1 * x = 22 * 12.3

4.1x = 270.6

Divide 4.1 to both sides:

x = 66
solmaris [256]3 years ago
5 0

Answer:

IMAO

Step-by-step explanation:

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Pharmaceutical companies prefers experimental studies to conducting surveys and observational studies because companies can manipulate or suggest methods easily to have good outcomes and they are able to directly observe the results. Experimental studies is a type of study in which a procedure and method is intentionally introduced.
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3 years ago
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Will give brainliest lots of points A is the midpoint of LB,Lb =6x-17 and AB=2x+3
NARA [144]
A is the mid point ==> AL = AB = 2AB
6x-17=2(2x+3) => 6x -17 = 4x +6 => 2x = 23 =>x=23/2
then just plug x into LB and AB
5 0
3 years ago
How much does 1 candy bar cost if 112 candy bars cost $78.00?
Alexxandr [17]
$0.70 per candy.
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5 0
2 years ago
A building casts a 21 foot shadow along the ground. A person 5 feet 3 inches casts a shadow 7 feet long.
Sonja [21]

Answer:

~28

Step-by-step explanation:

5 feet 3 inches is 5.25 feet.

We divide 7/5.25 which equals 1.3333333333333 (repeating)

That means we multiply 21 by 1.333333333333 which would round up to 28 feet. (the exact answer is 27.99999999999999999)

6 0
2 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
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