Answer:
Yes!
Step-by-step explanation:
We know that right triangles follow the Pythagorean Theorem, where
So we will put our side lengths into this formula, keeping in mind that c = the hypotenuse, which is the longest side. a and b are fairly arbitrary.
If this works, we know it's a right triangle.
1089 + 1936 = 3025
3025 = 3025
It worked! It's a right triangle!!
The vertices of AMNO are M (1,3), N (4,9), and O (7,3). The vertices of APQR are P (3,0), Q (4,2), and R (5,0) Which conclusion
Pavel [41]
Answer:
the correct answer should be C
Step-by-step explanation:
hope this helps you
Here's a way to do it.
Let 4e +2 = 5n +1 . . . . . . for some integer n
Then e = (5n -1)/4 = n + (n -1)/4
We want (n-1)/4 to be an integer, so let it be integer m.
... m = (n -1)/4
... 4m = n -1
... 4m +1 = n
Substituting this into our expression for e gives
... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1
e = 5m+1 for any integer m
Answer:
(a is size of side of triangle)
the perimeter of equilateral triangle =3a
or, 36=3a
Thus, a = 13cm
area of equilateral triangle
=√3/4*(a^2 )
=√3/4*(13^2)
=73cm^2
Answer:
line 3
Step-by-step explanation:
