Answer:
1) Event A = 2/3
Event B = 1/2
2) 1/2
Step-by-step explanation:
1)
Event A :
No. we need on dice = 4
Total numbers on dice = 6
Hence sample space of the event = 6
P( getting 4) = 4/6 = 2/3
Event B :
A coin has a head & a tail.
Hence sample space of the event = 2
But as we need tail only ,
P ( getting Tail ) = 1/2 [ if only tossed once ]
2)
Total numbers on a die = 6
Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )
Sample space of this event = 6
P (getting an odd number) = 3/6 = 1/2
N = N (1+0.20)^5
o
Here, that'd be 10000(1.20)^5, or 24883 trees.
To simplify <span>2x + 8 = -6, the easiest way is to manipulate the equation one step at a time:
</span>2x + 8 = <span>-6
</span>2x = <span>-14 (subtract 8 from both sides)
</span>x = -7 (divide both sides by 2)
The new area will be 320 in²
<em><u>Explanation</u></em>
Lin has a drawing with an area of 20 in² and she increases all sides by a scale factor of 4.
<u>The general rule</u> we need to use here.......
"<em>If the lengths of the sides in a shape are all increased by a scale factor of
, then the area will be increased by a scale factor of
"</em>
Here the sides are increased by a scale factor of 4. So, the area will be increased by a scale factor of 
Thus, the new area will be: 
In order to solve this, we need to figure out how much ONE student spends.

dollars per student.
If 10 student spent for lunch, we just have to multiply our number by how much each student spends.