Answer:
13 units
Step-by-step explanation:
(-1,5) and (4, -7)
To find the distance of two points, we use the distance formula:

Let's plug in what we know.

Evaluate the double negative.

Evaluate the parentheses.

Evaluate the exponents.

Add.

Evaluate the square root.

13 units
Hope this helps!
Answer:
2 real solutions
Step-by-step explanation:
Remember this messy thing?

The <em>quadratic formula</em>, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the <em>type</em> of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the <em>discriminant</em>. If it's non-negative, we'll have <em>real</em> roots, if it's negative, we'll have <em>complex roots</em>.
For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.
Answer:
8.6E23
Step-by-step explanation:
Radius = OC = OD
Solve for x:
10x -16 = 6x+2
4x = 18
x = 9/2 = 4.5
Sub 'x' back into OC
OC = 6(4.5) + 2 = 29
Radius = 29