your answer should be 58 correct me if I'm wrong.
For b it's 39 because you multiply 5 and 7 giving you 35 then add 4 Wich equals 39. I might be incorrect. check it out.
The rule for expressing a radical as a rational exponent is as follows:
![\sqrt[n]{x^y} = x^ \frac{y}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Ey%7D%20%3D%20x%5E%20%5Cfrac%7By%7D%7Bn%7D%20)
So, to find
![\sqrt[3]{27x^2y^3z^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27x%5E2y%5E3z%5E4%7D%20%20)
use that rule.
The cube root of 27 is 3, so the equation will start with 3.
Hope that helps!
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
Step-by-step explanation:
