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Blababa [14]
3 years ago
11

Explain how knowing 50 times 4 =200 helps you find 500 times 400.

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0

Given -

50 times 4 =200

Find out the  values of 500 times 400.

To prove

As given in the question

50 times 4 =200

i.e the above also written in the form as follows.

50 × 4 = 200

Now find out for 500 times 400.

500 times 400 is also written in the form as follows .

500 × 400 = 200000

Therefore the 500 times 400 is 200000.

Hence proved



Firdavs [7]3 years ago
4 0

To find 500 times 400 from 50 times 4 =200 : use commutative, associative properties and place value

500 times 400 \large{\boxed{\bold{=200000}}}

<h3>Further explanation</h3>

There are 3 properties in arithmetic operations that can be applied to arithmetic operations, namely: commutative, associative , and distributive properties

Commutative properties are mathematical operations of two numbers that are exchanged and produce the same results

a + b = b + a = c

a x b = b x a = c

this property applies to addition and multiplication operations.

Associative properties are mathematical operations of 3 numbers by grouping 2 numbers with parentheses and the location of the grouping is exchanged with the result that remains the same

(a + b) + c = a + (b + c) = d

(a × b) × c = a × (b × c) = d

Distributive properties are mathematical operations with 2 different arithmetic operations, by distributing numbers grouped in parentheses.

a × (b + c) = (a × b) + (a × c) = d

In the digit system, the value of a number depends on its place, or position, in the number.

Each digit is different place value.

the place value of the digits in a number: hundred thousands, ten thousands, one thousands, hundreds, tens, ones, decimal points, tenths, hundredths, thousandths, ten thousandths, hundred thousandths

From the task:

use the previous problem (50 times 4 = 200) to help solve 500 times 400.

50 times 4 = 200

in the form of arithmetic operations

50 x 4 = 200

or in place value

5 tens x 4 ones = 2 hundreds

we can use associative and commutative properties

(5\times10)\times4=200

(5\times4)\times10=200

=20\times10=200

so multiplication can be expressed in an interchangeable form because it has the same value

So to complete 500 x 400:

multiplying the whole numbers first then the zeros

The difference between first number operations and second number operations is the place value unit

 500 x 400

= 5 hundreds x 4 hundreds

= 5 x100 x 4 x 100 (there are 4 times ​​of 10)

= (5 x 4 x 10) x 10 x 10 x 10

⇒ (5 x 4 x 10) = from previous problem

= 200 x 10 x 10 x 10

\large{\boxed{\bold{=200000}}}

<h3>Learn more</h3>

the place value: 12,354,897

brainly.com/question/559183

brainly.com/question/840500

place-value patterns

brainly.com/question/98364

Keywords : place value, digit, number, times , commutative, associative

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Answer:

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Step-by-step explanation:

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A = 1/2 bh

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240+60 = 300

The total area is 300 ft^2

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Suppose the test scores for a college entrance exam are normally distributed with a mean of 450 and a s. d. of 100. a. What is t
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Answer:

a) 68.26% probability that a student scores between 350 and 550

b) A score of 638(or higher).

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d) The middle 30% of the test scores is between 411.5 and 488.5.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 450, \sigma = 100

a. What is the probability that a student scores between 350 and 550?

This is the pvalue of Z when X = 550 subtracted by the pvalue of Z when X = 350. So

X = 550

Z = \frac{X - \mu}{\sigma}

Z = \frac{550 - 450}{100}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 350

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 450}{100}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

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b. If the upper 3% scholarship, what score must a student receive to get a scholarship?

100 - 3 = 97th percentile, which is X when Z has a pvalue of 0.97. So it is X when Z = 1.88

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 450}{100}

X - 450 = 1.88*100

X = 638

A score of 638(or higher).

c. Find the 60th percentile of the test scores.

X when Z has a pvalue of 0.60. So it is X when Z = 0.253

Z = \frac{X - \mu}{\sigma}

0.253 = \frac{X - 450}{100}

X - 450 = 0.253*100

X = 475.3

The 60th percentile of test scores is 475.3.

d. Find the middle 30% of the test scores.

50 - (30/2) = 35th percentile

50 + (30/2) = 65th percentile.

35th percentile:

X when Z has a pvalue of 0.35. So X when Z = -0.385.

Z = \frac{X - \mu}{\sigma}

-0.385 = \frac{X - 450}{100}

X - 450 = -0.385*100

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65th percentile:

X when Z has a pvalue of 0.35. So X when Z = 0.385.

Z = \frac{X - \mu}{\sigma}

0.385 = \frac{X - 450}{100}

X - 450 = 0.385*100

X = 488.5

The middle 30% of the test scores is between 411.5 and 488.5.

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Answer:

<h2>33.2Km</h2>

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<h3>Time used for journey = </h3>

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<h3>changing 32 minutes to hours</h3>

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x = 32 min

x= 32 /60

x= 8/15 hours

<h3>Adding the 2hours to 8/15 hours</h3>

8/15 h + 2 h = 38 / 15

<h3>Using formula for distance</h3>

Distance = Speed × Time

Distance = 85km / h × 38 /15 h

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