Find the smallest positive integer that has a remainder of 1 after division by 2, a remainder of 2 after division by 3, a remain
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Answer:
Step-by-step explanation:
<h2>This is an independent event probability problem , that is the first event does not affect the occurrence of the second event.</h2>The sample space of the first die is S1= {1,2,3,4,5,6}
The sample space of the second die is S2= {1,2,3,4,5,6}
1. the probability that the first number cube shows a Four pr (4)=
2. the probability that the second number cube shows an odd number=
odd numbers in the sample space are 1,3,5= 3
pr(odd)
For the two event to happen the probability is =
We have been given volume of the cylinder which is 536.94 cubic inches. Now question says to find the radius of the cylinder.
Then we need to use formula of volume of cylinder which is given by :
We see that there are three unknown values in the formula: {volume, radius-r, height-h}
So to find any one of them we must know other two values.
Volume is given but height is missing. So just for explanation i'm going to use height of the cylinder h= 19 inches
Now plug the value of volume and height in above formula
take square root of both sides
3=r
Hence radius of the cylinder is 3 inches.