Given
Area of the regular pentagon is 6.9 cm².
Find out the perimeter of a regular pentagon
To proof
Formula
Area of regular pentagon is

As given in the question
area of regular pentagon = 6.9 cm²
now equating the area value with the area formula.

Now put
√5 = 2.24 ( approx)
put in the above equation

thus
a² = 4.01
a = √ 4.01
a = 2.0 cm ( approx)
As perimeter represented the sum of all sides.
i.e regular pentagon have five sides of equal length.
Thus
perimeter of the regular pentagon = 5 × side length
= 5 ×2.00
therefore the perimeter of the regular pentagon = 10cm
option c is correct
Hence proved
The quadratic equation with roots a and b is given by:

Here a=1/2 and b=-4.
So the equation is given by:

The quadratic equation is as shown above.
-4x-2 because u times the right side by-2
Answer:
A = 78.5 cm^2
Step-by-step explanation:
The area of a circle is given by
A = pi r^2
We know r =5 and pi = 3.14
A = 3.14 (5^2)
A = 3.14 (25)
A = 78.5 cm^2
Triangles are congruent
Step-by-step explanation:
Law of Side, Side, Angle
Thier base are same (PR).
Thier 1 side is equal to 2 inch (PS = RQ).
Thier 1 angle is equal (/_ PRQ = /_ RPS)
So, Its prove that both triangles are congruent.