Answer:
Given
Edge of a cube = 10cm
Length, l = 12.5 cm
Breadth, b = 10cm
Height, h = 8 cm
Find out
We have to find
i) Which box has the greater lateral surface area and by how much?
ii) Which box has the smaller total surface area and by how much?
Solution
(i)
Lateral surface area of a cube = 4 * (edge)2
= 4 * 102 cm2
= 400 cm2
Lateral surface area of a cuboid = 2 (lh + bh)
= 2 (12.5 * 8 + 10 * 8) cm2
= 2 (100 + 80) cm2
= 360 cm2
So, the lateral surface area of the cubical box is greater than cuboidal box by (400 cm2 – 360 cm2) which is 40 cm2.
(ii)
Total surface area of a cube = 6 * (edge)2
= 6 * 102 cm2
= 600 cm2
Total surface area of cuboid = 2 (lb + bh + lh)
= 2 (12.5 * 10 + 10 * 8 + 12.5 * 8) cm2
= 2 (125 + 80 + 100) cm2
= 610 cm2
Therefore, the total surface area of the cuboidal box is greater than the cubical box by (610 cm2 – 600 cm2) which is 10 cm2.
Answer:
BD = 21 units
Step-by-step explanation:
By applying mean ratio theorem in the given triangle ABC,
AD × CD = BD²
21 × 21 = BD²
BD² = (21)²
BD = 21
Therefore, measure of segment BD is 21 units.
Answer:
2
Step-by-step explanation:
(Pemdas)
Answer:
maybe
Step-by-step explanation:
you don't have a question to solve
