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3 years ago

A taxi service charges an initial $5 fee, plus $2 per mile driven.

Mathematics

2 answers:

Zanzabum3 years ago

5 0

A. 2m+5=total

<span>B. $305 </span>

____ [38]3 years ago

3 0

<h2>Answer:</h2>

A) c=2m+5

B) c=$ 305

<h2>Step-by-step explanation:</h2>

Let us suppose m represents the number of miles driven.

and let c represents the cost charged after m miles are driven.

It is given that:

A taxi service charges an initial $5 fee, plus $2 per mile driven.

This means that the equation that represent the situation is given by:

c= 2m+5

Now we are asked to find the value of c when m=150

Hence, the cost is given by:

c=2×150+5

c=$ 305

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3 years ago

You make 12 equal payments you pay a total of $1308. how much is each payment? step by step

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Answer:

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2 years ago

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On a farm there are three-legged-cows and chickens. There are total of 127 heads and 353 legs. How many three-legged-cows are on

olga nikolaevna [1]

Answer: There are 99 three-legged-cows and 28 chickens.

Step-by-step explanation:

Let x be the number of three-legged-cows and y be the number of chickens.

Number of legs in chicken = 2

The according to the question, we have the following equations :-

$\text{For heads }x+y=127------(1)\\\\\text{For legs }3x+2y=353------(2)$

Multiplying 2 to the equation (1), we get

$2x+2y=254--------(3)$

Now, subtract equation (3) from (2), we get

$x=353-254=99$

Put x= 99 in (1), we get

$99+y=127\\\\\Rightarrow\ y=127-99=28$

Hence, there are 99 three-legged-cows and 28 chickens.

6 0

3 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)