Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
It looks like there’s a pattern going on here so i believe it would be B
Add, then subtract and that’s your answer!
Actual cost of the car bought by Alvarez family = $2000
Amount of down payment made by the Alvarez family = $500
Outstanding amount
that has to be paid by the Alvarez family = (2000 - 500) dollars
= 1500 dollars
Number of equal payments to pay the outstanding balance = 5
So
Payment that has to be made
by the Alvarez family in 5 equal parts = 1500/5 dollars
= 300 dollars
So the Alvarez family has to make 5 payments of $500 to complete the outstanding amount of the car. I hope the procedure is clear enough for you to understand.
Answer:
f(x) = 17x - 18
y=17x-18
y=17(33)-18
y=561-18
y=543
f(x)=543
Step-by-step explanation:
