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Citrus2011 [14]
3 years ago
12

Help please and thank you

Mathematics
2 answers:
kodGreya [7K]3 years ago
7 0

Answer:

if I'm not mistaken it's 28

Step-by-step explanation:

x+4=32

x=28

Viefleur [7K]3 years ago
4 0

Answer:

You can do it!

Step-by-step explanation:

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What is the square root of -625
loris [4]

Answer:

  25i

Step-by-step explanation:

Your calculator or your knowledge of powers of 5 will tell you that √625 is 25. The minus sign makes the root imaginary.

  \sqrt{-625}=\sqrt{(-1)(25^2)}=25\sqrt{-1}=25i

6 0
4 years ago
Read 2 more answers
If the two consecutive numbers is 23 , find them​
Iteru [2.4K]
<h2>(☞^o^) ☞</h2><h2>Here's your answer </h2>

Step-by-step explanation:

Let the two consecutive natural numbers be x and x+1

Now, according to the problem

x+(x+1)=23

⇒ 2x+1=23

⇒ 2x=23−1

⇒ 2x=22

⇒ x=22÷2=11

The one number is 11

The next number is x+1=11+1=12

Hence the numbers are 11 and 12.

Be my Friend...

5 0
2 years ago
Simplify 7.06 ×1000 - 1976 ÷100​
Mkey [24]

\huge\text{Hey there!}

\large\text{7.06}\times\large\text{1,000 - 1,976}\div\large\text{100}\\\large\text{7.06}\times\large\text{1,000 = \boxed{\bf 7,060}}\\\large\text{7,060 - 1,976}\div\large\text{100}\\\large\text{1,976}\div\large\text{100 = 494}\div\large\text{25 = \boxed{\bf 19.76}}\\\large\text{7,060 - 19.76}\\\mathsf{= \boxed{\bf \ Answer: \dfrac{17,6006}{25}\ or\ 7,040.24}}\leftarrow\large\text{either of those choices should}\\\large\text{work because they are both equivalent to each other }

\large\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

7 0
3 years ago
If x=7+4√3,find the value of √x+¹/√x​
Tcecarenko [31]
<h2><em>Answer:</em></h2><h2><em>Answer:x = 7+4√3</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√3</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√31/√x = 1/(2+√3)</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√31/√x = 1/(2+√3)Multiplying both numerator and denominator by 2 - √3, we get</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√31/√x = 1/(2+√3)Multiplying both numerator and denominator by 2 - √3, we get1/√x = (2-√3)/(2-√3)(2+√3) = (2-√3)/(2²-√3²) =</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√31/√x = 1/(2+√3)Multiplying both numerator and denominator by 2 - √3, we get1/√x = (2-√3)/(2-√3)(2+√3) = (2-√3)/(2²-√3²) =1/√x = 2-√3</em></h2><h2 /><h2><em>Answer:x = 7+4√3To find √x we proceed,√x = √(7+4√3)√x = √(7+2x2√3)√x = √(7+2√3x4)√x = √(3+4+2√3x4)….. {writing 7 = 3+4}If we observe RHS of √x we observe form of√(a² + b² +2ab) where a=√3 and b =√4Hence, √x =√(√3 +√4)² = √3 + √4 = 2+√3√x = 2+√31/√x = 1/(2+√3)Multiplying both numerator and denominator by 2 - √3, we get1/√x = (2-√3)/(2-√3)(2+√3) = (2-√3)/(2²-√3²) =1/√x = 2-√3Hence √x +1/√x = 2+√3 +2 -√3 = 4</em></h2><h2 />
4 0
3 years ago
Determine whether 5, 238 is divisible by 2, 3, 4, 5, 6, 9, or 10.
Gelneren [198K]

Answer:

2, 3, 6

Step-by-step explanation:

Simply try each value using long division.

2:

Since 5,238 ends in an even number, that automatically means it is divisible by 2.

5238/2=2619

Now for 3:

5238/3=1746 no remainder or decimal, so 3 also works

4:

You can either do long division again with 4, or you can see if 5238 divided by 2 (5238/2) is also divisible by 2. Since 2619 doesn't end in an even number, 4 is a no go.

Long division 5238/4=1309.5 decimal here, so 4 isn't an answer

5:

This is also very easy, simply check if the number ends in 0 or 5. Since 5,238 does not, 5 doesn't work either.

6:

You can do the same thing as with 4, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 2. Since 1746 ends in an even number, 6 also works.

Long division: 5238/6=873

9:

You can do the same thing as with 6, except this time trying to find if 5238 divided by 3 (5238/3) is divisible by 3.

1746/3=548 with a remainder of 2, which means 9 doesn't work

Long division: 5238/9=548.66 repeating

10:

Finally, 10 is another easy one. Simply check if the number ends in 0. 5,238 does not, so 10 doesn't work.

5 0
2 years ago
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