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andreyandreev [35.5K]
3 years ago
5

Vince had c CDs until he won 21 more in a contest. Write an expression that shows how many CDs Vince has now.

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
Because 'more' means that 21 is added to the original amount: c + 21.
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Multiply and simplify the following expression -4√15 x(-√3)
larisa [96]

Answer:

\large\boxed{12\sqrt5}

Step-by-step explanation:

\text{Use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\-----------------\\\\-4\sqrt{15}\cdot\left(-\sqrt3\right)=4\sqrt{(15)(3)}=4\sqrt{5\cdot3\cdot3}=4\sqrt5\cdot\sqrt9\\\\=4\sqrt5\cdot3=12\sqrt5

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Ashlyn and her friends are making gingerbread houses. They need to divide 28 packages of gumdrops between 7 friends. There are 2
leonid [27]

Answer:

100 gumdrops per person

Step-by-step explanation:

We know that there are 28 packages and each one has 25.  So just multiply 28 by 25 and you get 700 gumdrops in total.  Finally because there are seven friends in total you divide 700 by 7 and get 100 per person.

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BaLLatris [955]

Answer:

247 ft is the correct answer

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2 years ago
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Write in function notation;<br> y= 5x + 2
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In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
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