Answer:
13. x = 52.8°
14. 663.65 ft
15. 30.7 ft
Step-by-step explanation:
The mnemonic SOH CAH TOA is intended to remind you of the relations between sides of a right triangle and trig functions of the acute angles.
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<h3>13.</h3>
The sides adjacent and opposite the angle are marked. The relevant trig relation is ...
Tan = Opposite/Adjacent
tan(x°) = 2.5/1.9
The angle is found using the inverse tangent function:
x° = arctan(2.5/1.9) ≈ 52.8°
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<h3>14.</h3>
Again, the tangent relation comes into play. The given values are the side opposite and the angle, and we are asked for the side adjacent.
Tan = Opposite/Adjacent
tan(11°) = (129 ft)/(distance to shore)
distance to shore = (129 ft)/tan(11°)
distance to shore ≈ 663.65 ft
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<h3>15.</h3>
In this scenario, the given angle is opposite the given side of the triangle. The measure of the hypotenuse is needed.
Sin = Opposite/Hypotenuse
sin(71°) = (29 ft)/(ladder length) . . . . substitute given information
ladder length = (29 ft)/sin(71°) . . . . . . solve for ladder length
ladder length ≈ 30.7 ft
Sorry I can't find the answer but find other users sorry
Answer:
(3,2)
Step-by-step explanation:
Answer:
37 and -18
Step-by-step explanation:
Let one number be x and other y
1 x + 1 y = 19 .............1
1 x -1 y = 55 .............2
Eliminate y
multiply (1)by 1
Multiply (2) by 1
1 x 1 y = 19
1 x + -1 y = 55
Add the two equations
2 x = 74
/ 2
x = 37
plug value of x in (1)
1 x + 1 y = 19
37 + 1 y = 19
1 y = 19 -37
1 y = -18
y = -18
37 and -18
9514 1404 393
Answer:
5 miles
Step-by-step explanation:
Time/speed/distance problems can be worked a number of ways. Here, we want to know the distance walked. We know the total time and the total distance and the two different speeds. So, we can use a variable to represent the value we want to know: w = distance walked (in miles).
The total time is 9:00 -6:50 = 2:10 = 2 1/6 hours = 13/6 hours.
The total time is the sum of times for the two parts of the trip: walking and riding.
walking time = walking distance/walking speed
= w/3
riding time = riding distance/riding speed
= (20-w)/30
The total time is that given above:
w/3 +(20-w)/30 = 13/6
10w +(20 -w) = 65 . . . . . . . . multiply by 30
9w = 45 . . . . . . . . . . . . subtract 20, collect terms
w = 5 . . . . . . . . . . . divide by 9
The girl walked 5 miles.
