Answer:
Maximum safe height can be reached by ladder = 15.03. ft
Step-by-step explanation:
Given,
Let's assume the maximum safe height of wall = h
angle formed between ladder and ground = 70°
length of ladder = 16 ft
From the given data, it can be seen that ladder will form a right angle triangle structure with the wall
So,from the concept of trigonometry,



=> h = 16 x 0.9396
=> h = 15.03 ft
So, the maximum safe height that can be reached by the ladder will be 15.03 ft.
Answer:
12.5
Step-by-step explanation:
y varies inversely as x.
y = k/x
10 = k/20
200 = k
The constant proportion k is 200.
16 = 200/x
Cross multiply.
200 = 16x
200/16 = x
x = 12.5
9514 1404 393
Answer:
31.243 units
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.
Sin = Opposite/Hypotenuse
sin(30°) = BE/100
BE = 100·sin(30°)
Then ...
Tan = Opposite/Adjacent
tan(58°) = BE/x
x = BE/tan(58°) = 100·sin(30°)/tan(58°)
x ≈ 31.243 . . . . units
_____
<em>Comment on the figure</em>
The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.
Answer: Choice C. p = 250(0.79)^t
Work Shown:
p = a*b^t
p = a*(1+r)^t
p = 250*(1+(-0.21))^t
p = 250(0.79)^t
Note that r = -0.21 is negative to indicate we have exponential decay.
Answer:
Step-by-step explanation:
1.

2.
