A system of equations is a collection of two or more equations with the same variables. When solving this system, u need to find the unknown variables. One way of solving a system of equations is by substitution.
example :
2x + 2y = 6 (equation 1)
3x + y = 4 (equation 2)
we need to pick a variable and isolate it. The easiest one to pick since it is already by itself is the y in the second equation.
3x + y = 4.....subtract 3x from both sides
y = -3x + 4
now we can sub -3x + 4 in for y in the 1st equation...u have to make sure u sub it back into the 1st equation and not the same equation u used to find it.
2x + 2y = 6.....sub in -3x + 4 in for y and solve for x
2x + 2(-3x + 4) = 6...distribute thru the parenthesis
2x - 6x + 8 = 6...subtract 12 from both sides
2x - 6x = 6 - 8...simplify
-4x = -2...divide both sides by -4
x = -2/-4
x = 1/2
now that we have a numerical number for x, u can sub this back into either of ur equations to find a numerical answer for y.
y = -3x + 4...when x = 1/2
y = -3(1/2) + 4
y = -3/2 + 4
y = -3/2 + 8/2
y = 5/2
so ur solution is : (1/2,5/2) <===
and u can check ur answers by subbing them into ur equations to see if they satisfy both equations...because for it to be a solution to this system, it has to satisfy both equations and not just one of them
< right angle is the right answer
A)Plugging in our initial statement values of y = 16 when x = 10, we get:
16 = 10k
Divide each side by 10 to solve for k:
16/10=
k = 1.6
Solve the second part of the variation equation:
Because we have found our relationship constant k = 1.6, we form our new variation equation:
y = 1.6x
Since we were given that x, we have
y = 1.6()
y = 0
B)Plugging in our initial statement values of y = 1 when x = 15, we get:
1 = 15k
Divide each side by 15 to solve for k:
1/15
=15k
k = 0.066666666666667
