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zalisa [80]
3 years ago
7

Help please. Due Friday

Mathematics
1 answer:
devlian [24]3 years ago
5 0
Right triangle

1) 75.6cm
2)10.14ft
3)16ft

Entire triangle

1)162cm
2)30.94ft
3)20ft
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A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
Does this graph represent a function?Why or why not?
cestrela7 [59]

No, it does not have a straight line. (A)


4 0
3 years ago
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Help!!! Correct answer please and thank you (:
Elan Coil [88]

Answer:

c

Step-by-step explanation:

425.78 x .0765 is equal to 32.57

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3 years ago
What are perfect numbers? Find the only 3examples below 500
liubo4ka [24]

The first two are 6 and 28. The factors of 6 add up to the same thing as 6.

Six

1 * 2 * 3 = 6

1 + 2 + 3 = 6

Twenty eight

1 + 2 +  4 + 7 + 14 = 28 (the multiplication is not the same as for 6).

Four hundred ninety Six

This one is kind of hard to believe

It is 16 * 31

1 + 2 + 4 + 8 + 16 + 248 + 124 + 62 + 31 = 496

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a minor league baseball team plays 95 games in a season. if the team won 15 more than three times as many games as they lost, ho
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