Answer:
1.) yuma
2.) Spanish
3.) 8th
4.) two years
5.) 8
6.) united
7.)aztec
8.) ?
9.) ?
10.) 1993
Step-by-step explanation:
To scale them up by 5 you just have to multiply...
.05 x 5 = .25
1/2 x 5 = 5/2 = 2 1/2 = 2.5
7 x 5 = 35
13 x 5 = 65
25 = 125
102 = 510
Step-by-step explanation:
Given:
population mean, mu = 57 lb
population standard deviation, sigma = 6.3 lb
Sample mean, x = 60.2 lb
Sample size, n= 45
Null hypothesis x = mu (i.e. sample mean is not greater than usual, using a significance level of 0.05)
Here we have a case where population mean and standard deviation are known (given).
We calculate the z-score
z=(x-mu)/(sigma/sqrt(n))
= (60.2-57)/(6.3/sqrt(45))
= 3.41
P(x>mu) = P(z>3.41) = 0.99968 >> 0.95 (one sided tail)
Therefore we can reject the null hypothesis and accept the alternate hypothesis that fish are larger than usual.
Answer:
Step-by-step explanation:
y-8=3/5(x-5)
multiply 3/5 times x and -5
y-8=3/5x-3
then add 8
y=3/5x+5
Answer:
24 minutes, 2:36 pm
Step-by-step explanation:
As working with hours is difficult because it does not use decimal system, lets work with minutes, not hours.
So, the clock is set to work normal at 3:00 pm and we need to get the minutes lost three days after. We know that, as 1 day has 24 hs, 3 days have 72 hours. Then, as our clock loses 2m after every 6 hs, we need to see how many 6hs are there in 72 hs. We do this bt dividing 72 by 6:
72/6 = 12
So, in 72 hours we will have 12 periods of 6hs. As our clock loses 2m after every 6 hs, in 3 days we will lose 2m 12 times. This is:
12 * 2 = 24
The clock loses 24 minutes.
Now we need to see the time it will read.
If there were no problems, the clock should read 3:00 pm after 3 days (72hs). But, as it lost 24 minutes, it will read 2:36 pm, it is, 24 minutes before 3:00 pm.