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Orlov [11]
3 years ago
7

HELP!!!!!ASAP!!!!!!

Mathematics
1 answer:
dlinn [17]3 years ago
6 0

Answer:

\sin( 115 \degree)  = 0.906

Step-by-step explanation:

The general point on a unit circle is given by

x =  \cos( \theta)

y =  \sin( \theta)

where

\theta = 115 \degree

is the terminal side of the angle in standard position.

Therefore

x =  \cos( 115 \degree)

y =  \sin(115 \degree)

lies on this circle

This angle intersects the unit circle at

( - 0.423,0.906)

Hence we must have

\cos( 115 \degree)  =  - 0.463

\sin( 115 \degree)  = 0.906

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Arianna is buying plants for her garden. She buys 15 flowering plants for $96. Pink flowering plants sell for $8, and purple flo
Zielflug [23.3K]

Answer:

  • 7 pink flowering plants

Step-by-step explanation:

  • Total number of plants = 15
  • Total cost = $96
  • Cost of pink flowering plant = $8
  • Cost of purple flowering plant = $5

<u>Let x and y be the number of plants bought. Then we have equations:</u>

  • 8x + 5y = 96
  • x + y = 15 ⇒ y = 15 - x

<u>Substituting y in the first equation:</u>

  • 8x + 5y = 96
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  • 8x + 75 - 5x = 96
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Correct option is the second one

3 0
3 years ago
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What is point d on the coordinate
taurus [48]

Algebra

The formula to find the coordinate is (x,y)

Meaning, point D is (1,4)

7 0
3 years ago
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A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

\tan \theta = \dfrac{1}{10}

\theta = \arctan 0.1 \approx 5.711^\circ

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10.    The height h or rise is the side opposite the small angle.

\sin\theta = \dfrac h c

h = c \sin \theta

We could just take the sine of the angle we got but let's get it from the tangent exactly.

\cos^2 \theta + \sin ^2 \theta = 1

Dividing by squared cosine

1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)

(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101

h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199

Answer: (b) Rise of 0.199 km

6 0
4 years ago
Rewrite the equation by completing the square x^2+11x+24=0
Kobotan [32]

Answer:

x= -3 , -8

Step-by-step explanation:

8 0
4 years ago
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A ship leaves port at noon at a bearing of 293º. The ship's average rate of speed over this
Pavlova-9 [17]

Answer:

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Detailed explanation and calculation is shown in the image below.

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