Answer:
(ab - 6)(2ab + 5)
Step-by-step explanation:
Assuming you require the expression factorised.
2a²b² - 7ab - 30
Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term
product = 2 × - 30 = - 60 and sum = - 7
The factors are - 12 and + 5
Use these factors to split the ab- term
= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )
= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term
= (ab - 6)(2ab + 5) ← in factored form
Answer:
160 degrees
Step-by-step explanation:
Step 1: A straight line is 180 degrees. So 180 - 100, is 80 degrees. as the opposite angle measurement of the 100 degree.
Step 2: An isosceles triangle has two equal angle measurements, so two of its angles are 80 degrees.
Step 3: All angles in a triangle equal 180 degrees. So add them up (we will call the missing angle, Z) 180 = 80+80+Z. which equals 180= 160+z
Step 4: Solve it. You subtract 160 from both side which comes out to 20 = Z.
Step 5: Now you have the opposite angle of X. Going back to step 1, A straight angle is 180 degrees. 180 - 20 = 160. X = 160 degrees
Answer:
Let the original number be x
Successor is defined as the number which comes immediately after a particular number.
also, the successor of a whole number is the number obtained by adding 1 to that number.
Then, the successor of a number x is, x+1
As per the given condition :
we have;

Using distributive property on LHS (i.e,
)
Then, we have
5x+5+x=83
Combine like terms;
6x+5=83
Subtract 5 from both the sides we get;
6x+5-5=83-5
Simplify:
6x=78
Divide both side by 6,

Simplify:
x =13
Therefore, the original number x is, 13
<span> 7/4 = 1.75000 is the other fraction</span>
Answer:
The range of possible values for the third side called c is;
11 > c or c < 11
Step-by-step explanation:
Here in this question, we are concerned with giving the range of the third side of the triangle.
What we will be using to get this range is the triangle inequality theorem.
Mathematically, the sum of the length of the two sides must be greater than the length of the third side.
So let’s call the third side c
Thus, the range of values we are to work with is;
5 + 6 > c
11 > c