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valentina_108 [34]
3 years ago
9

I really need help. Pleeease. I'm begging you!

Mathematics
1 answer:
Temka [501]3 years ago
5 0

the answer is totally numbers

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Solve this problem on paper using all four steps. A girl scout troop sold cookies. If the girls sold 5 more boxes the second wee
Varvara68 [4.7K]
This is a problem where you should make an equation.
Let's say x is the first week. It would mean
First Week : x
Second Week : x + 5
Third Week : 2(x+5)
You need to add these up to make your equation. Your equation will look something like this :
x+x+5+2(x+5) = 431
Now you simplify.
2x+5+2x+10 = 431
4x+15 = 431
4x = 416
x = 104
That means they sold 104 Boxes in the First Week.
104+5=109
So they sold 109 Boxes the Second Week.
109 x 2 = 218
And they sold 218 Boxes the Third Week.

I hope I was useful!
3 0
3 years ago
Read 2 more answers
Help with this pls!!!
Pepsi [2]
B is the answer I know because I took the test
4 0
2 years ago
85 points, Brainliest, ill report random answers>ban
Leya [2.2K]

 all the coordinates of the original triangle have been multiplied by 1/2

A (-4,-6) x 1/2 = -2,-3

B (-8,2) * 1/2 = -4,1

C (-2,4)  *1/2 = -1,2

 so the scale factor is 1/2

 Answer is B

8 0
3 years ago
Read 2 more answers
please someone help I know the answer but I don't know how to place it on the scales below. (15 Points)
guapka [62]

Given:

a. 35% of 150 g

b. 113% of $55

To find:

The correct values for the given blanks.

Solution:

a. 35% of 150 g

Here, the percent part is 35% and percent whole is 100%.

35% of 150 g is:

\dfrac{35}{100}\times 150=52.5

So, the number part is 52.5 g and the whole number is 150 g.

Therefore, the percent part is 35%, number part is 52.5 g and the whole number is 150 g.

b. 113% of $55 g

Here, the percent part is 113% and percent whole is 100%.

113% of $55 is:

\dfrac{113}{100}\times 55=62.15

So, the number part is $62.15 and the whole number is $55.

Therefore, the percent part is 113%, number part is $62.15 and the whole number is $55.

6 0
3 years ago
Postulate or theorem can be used to prove th ABC= AEDC. D A. SSS O B. ASA C. AAS D. SAS​
telo118 [61]

Answer:

sas

Step-by-step explanation:

4 0
3 years ago
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