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3 years ago

The perimeter of the figure is 20 inches. What is the missing side length?

Mathematics

2 answers:

Agata [3.3K]3 years ago

4 0

You would do the whole perimeter (the length of all the sides added up) minus the three known sides to find the missing side.
20 - 4 - 4 - 8 = 4, so the answer would be 4 inches.

Eddi Din [679]3 years ago

3 0

When finding perimeter you add all the sides up.
So if you're looking for the perimeter, which is 20, just add 8 + 4 + 4
That equals 16.
So do 20 - 16.
Then you get your answer which is 4 in

You could also do:
20-8
That's 12
Then 12-4
That's 8
Then do 8-4
To get you your answer of 4 in

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X + 2y = 72 what are my x and y points on a graph for this equation? please explain

pishuonlain [190]

To find the y int, sub in 0 for x and solve for y
0 + 2y = 72
2y = 72
y = 72/2
y = 36....so ur y int is (0,36)

to find the x intercept, sub in 0 for y and solve for x
x + 2(0) = 72
x = 72....and ur x int is (72,0)

6 0

3 years ago

The manufacturer of an airport baggage scanning machine claims it can handle an average of 530 bags per hour. (a-1) At α = .05 i

fenix001 [56]

Answer:

Null hypothesis: $\mu \geq 250$

Alternative hypothesis: $\mu < 250$

$p_v =P(t_{15}$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and the the actual mean is not significantly lower than 530 at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=510$ represent the mean for the sample

$s=50$ represent the standard deviation for the sample

$n=16$ sample size

$\mu_o =530$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the claim thet the handle on average is 530 bags per hour:

Null hypothesis: $\mu \geq 530$

Alternative hypothesis: $\mu < 530$

We don't know the population deviation and the sample size is lees than 30, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{510-530}{\frac{50}{\sqrt{16}}}=-1.60$