The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
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There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Answer:
5/8
Step-by-step explanation:
5/8=0.6.25
0.625> all the other numbers
Answer:
Jason can plug what x equals (6.5) back into the equation everywhere x is and solve! If the answers on both sides equal each other (example 3=3) then that means his answer is correct.
Step-by-step explanation:
Facts and math.