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lions [1.4K]
2 years ago
11

The perimeter of the figure is 20 inches. What is the missing side length?

Mathematics
2 answers:
Agata [3.3K]2 years ago
4 0
You would do the whole perimeter (the length of all the sides added up) minus the three known sides to find the missing side.
20 - 4 - 4 - 8 = 4, so the answer would be 4 inches.
Eddi Din [679]2 years ago
3 0
When finding perimeter you add all the sides up.
So if you're looking for the perimeter, which is 20, just add 8 + 4 + 4
That equals 16.
So do 20 - 16.
Then you get your answer which is 4 in

You could also do:
20-8
That's 12
Then 12-4
That's 8
Then do 8-4
To get you your answer of 4 in
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First Divide both sides by -5.73

-5.73q/-5.73=97.41/-5.73

Answer: q=-17

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Find sin(a) in the triangle.
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Read 2 more answers
I need help with this one I’m not so sure about my answer (〒﹏〒) <br> 8+10v–4v
Ket [755]

Answer:

8+6v

Step-by-step explanation:

Hey There!

So all you have to do is combine like terms (10v and -4v)

10v-4v=6v

So your answer would be 8+6v

6 0
3 years ago
What is the value of 1 over 2 x+3.4y when x=3 and y = 4?​
gavmur [86]

Answer:

The value of the given expression is 27.1

Step-by-step explanation:

We are given an expression of two variable x and y.

We need to find the value of expression at x = 3 and y = 4

So first put x = 3 and y = 4 into expression and simplify

1/2 x 3 (3) + 3.4 x 4

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➡️ 27/2 + 13.6

➡️ 13.5 + 13.6

Now, add both of the numbers together. ( as an addition problem)

Therefore, when you ad the 2 together, you get the total of 27.1

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%20x%5E%7B2%7D-10x%2B25%7D%2B25%2B12%5Csqrt%7Bx%7D%20%3D15%5Csqrt%7Bx%7D" id="TexFor
vodomira [7]

Step-by-step explanation:

\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

8 0
3 years ago
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