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3 years ago

Jeremy drew a polygon with four right angles and four sides with the same length name all the polygons that he have done

Mathematics

1 answer:

erik [133]3 years ago

6 0

The most-specific name for such a polygon is square.

It can also be called a rectangle, rhombus, parallelogram, or quadrilateral.

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What percent of 70 equals 21

Misha Larkins [42]

Answer:

30% of 70 = 21

Step-by-step explanation:

21/70 = .3

.3=30%

4 0

2 years ago

Read 2 more answers

Darren wants to grow tomatoes and herbs so he can make his own fresh pizza sauce. Darren's planter box is seven feet long and fo

n200080 [17]

Answer:

The volume of soil in Darren's planter box is 56 feet³

Step-by-step explanation:

The formula of the volume of a rectangular box is V = l × w × h, where l is its length , w is its width and h is its height

∵ Darren's planter box is seven feet long and four feet wide

∴ l = 7 feet

∴ w = 4 feet

The volume of the soil is equal to the volume of the box using the height of the soil, because the soil takes the shape of the box, so they have the same dimensions of the base

∵ Darren fills the planter box with soil to a height of two feet

∴ h = 2 feet

- Substitute the values of l, w and h in the formula of the volume

∵ V = 7 × 4 × 2

∴ V = 56 feet³

The volume of soil in Darren's planter box is 56 feet³

3 0

2 years ago

Read 2 more answers

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

A boat leaves a dock and travels 9 miles due north and 12 miles due west. Find how far the boat is from the dock. Type the corre

adelina 88 [10]

Answer:

15 miles

Step-by-step explanation:

Let's say the dock is at the origin on a coordinate plane and each unit is 1 mile. If the boat travels 9 mile due north, that means that we move up from the origin (0, 0) 9 units to point A (0, 9). Now, this boat moves 12 miles due west, so we will go 12 units to the left of (0, 9) to point B (-12, 9). See the attached drawing (sorry for the crudeness).

Notice that this is a right triangle with legs of 9 and 12. That means the distance from the boat to the dock is just the hypotenuse, so use the Pythagorean Theorem: distance = $\sqrt{9^2+12^2} =\sqrt{81+144} =\sqrt{225} =15$