log (2x)=3 I don't remember how I got my awn see
<span>1 x 40 = 40
2 x 20 = 40
4 x 10 = 40
5 x 8 = 40
8 x 5 = 40
10 x 4 = 40
20 x 2 = 40
40 x 1 = 40
???</span>
The correct question is
<span>The product of two consecutive positive integers is
11 more than their sum. find the integers.
Let
x-------> the first </span>positive integer
x+1-----> the second consecutive positive integer
we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
x²-x-12=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=4
therefore
the numbers are
x=4
x+1=5
the answer isthe numbers are 4 and 5
65. change 11 5/6 to a mixed number:
71/6-17/18
multiply 6 and 71 by 3 which equals 18 so now the denominators are the same
213/18-17/18=196/18
to simplify divide 196 and 18 by 2
196÷2=98
18÷2=9
now divide 98 by 9
98÷9=10 (rounded to whole number)
9×10=90
so to get 98 you add 8
your answer is 10 8/9
66. change both fractions to a mixed number
9 5/9=86/9
8 1/6=49/6
multiply 86 and 9 by 2
86×2=172
9×2=18
multiply 49 and 6 by 3
49×3=147
6×3=18
now subtract :
172/18-147/18=25/18
divide 25 by 18
25÷18=1 (rounded whole number)
18×1=18
to get 25 you add 7
your answer is 1 7/18
hope this helped