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3 years ago

You make skateboard ramps by cutting pieces from a board that is 12 1/2 feet long.

1 answer:

5 0

The length of the ramp is unknown.
If 6 ramps were cut from a board that is 12 1/2 feet long, the ramps would be about 2 feet long each which seems like a reasonable answer. The questions regarding how many boards are cut would need the length of the ramps. Lets say that the length is x. You can get 12 1/2 divided by x boards. In order to find out how much is left over, take the number of boards made, multiply it by how long they are. This product is then subracted from 12 1/2.

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Solve for x. 2x + 5 = x - 8

Gemiola [76]

2x+5=x-8
-x on both sides
x+5=8
-5 on both sides
x=-13

7 0

3 years ago

Plz help if correct ill give brailiest

Kamila [148]

Answer:

That first one is the answer

3 0

3 years ago

Read 2 more answers

horrorfan [7]

Step-by-step explanation:

charging the phone for 1 minute ,it has 2%

i.e,1----->2

After 2 minutes from that time ,i.e total 3 minutes

it has 6% charge

i.e,3--------->6

from the both the above cases ,1 minute provide 2%=6/3

Hence,

for getting 50%charge=50/2

=25 min

and,for 90 %charge=90\2

=45 min

8 0

2 years ago

Simplify the expression. 16 x 4 -4

Lorico [155]

Answer:

The answer is 60

Step-by-step explanation:

16 x 4 - 4

64 - 4

Hope this helped!

7 0

2 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago