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prisoha [69]
3 years ago
9

-2*f(6-)-7*g(-7)= ???

Mathematics
2 answers:
const2013 [10]3 years ago
5 0

Answer:

12f+49g

Step-by-step explanation:

-2f(-6)-7g(-7)\\12f+49g

Leni [432]3 years ago
5 0

Answer:

11

Step-by-step explanation:

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Can someone please help me with question 7?
storchak [24]

The goal is to raise AT LEAST $180, so this automatically indicates that the amount of keychains sold with the price must be the same or more than $180.

k = number of keychains

each keychain is $2.25

2.25k ≥ 180

divide both sides by 2.25 to get the k alone

k ≥ 80

The answer is 2.25k ≥ 180, k ≥ 80

(Hope this isn't confusing)


6 0
3 years ago
8.75 x 10 ^3 in standard form
Sveta_85 [38]

Answer:

8.75×10^3

Step-by-step explanation:

here is the answer

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Solve for x: 7+4x=13+x
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4 0
3 years ago
Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

⇒ log(kaa) = k × log(a)

or

⇒ log(ka²) = k × log(a)

Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

3 0
3 years ago
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