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Natalka [10]
4 years ago
12

Find the remainder when 2x^4-6x^3+2x^2-x+2 is divided by x+2

Mathematics
2 answers:
dybincka [34]4 years ago
7 0
P(x)=2x^4-6x^3+2x^2-x+2 \ \ \ and\ \ \ x_0=-2\\\\the\ remainder:\\\\R(x)= 2(-2)^4-6(-2)^3+2(-2)^2-(-2)+2=\\\\=2\cdot16-6\cdot(-8)+2\cdot4+2+2=32+48+8+4=92
finlep [7]4 years ago
4 0
The answer to the problem would be 2x³-10x²+22x-45+92/(x+2)
So the remainder is 92.
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