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professor190 [17]
3 years ago
7

|x-4|=2 solve the absolute value equation ​

Mathematics
1 answer:
Masteriza [31]3 years ago
6 0

Answer:

x=6 or x=2

Step-by-step explanation:

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A TV has a height:width in a ratio 9:16 In a scale drawing the height is 4.5 cm. What would the width be?
ASHA 777 [7]
A.T.Q,
Let, the width = x
It would be: 9/16 = 4.5/x

x = 4.5/9 * 16
x = 16/2
x = 8

So, your final answer & width would be 8 cm

Hope this helps!
3 0
3 years ago
Read 2 more answers
URGENT HELP PLEASE!
KonstantinChe [14]

Answer:

Perpendicular lines (c)

3 0
3 years ago
Can somebody solve this?
erastova [34]

Answer:

∠ABC = 46°

Step-by-step explanation:

DB and BC are of same length (radius), making it an isosceles triangle.

The base of the triangle is the same at 23°, a total of 46°.

180° - 46° = 134°

But we need ∠ABC, and since points DBA lie on the circumference, it's a straight line.

Therefore, 180° - 134° = 46°

7 0
3 years ago
Write a series of rigid motions that transform pentagon ABCDE to pentagon A′B′C′D′E′
worty [1.4K]

Answer:

We need the following three rigid motions:

i) Reflection around y-axis, ii) Translation three units in the -y direction, iii) Translation four units in the -x direction.

Step-by-step explanation:

We need to perform three operations on pentagon ABCDE to create pentagon A'B'C'D'E':

i) Reflection around y-axis:

(x',y') = (-x,y) (Eq. 1)

ii) Translation three units in the -y direction:

(x'',y'') = (x', y'-3) (Eq. 2)

iii) Translation four units in the -x direction:

(x''',y''') = (x''-4, y'') (Eq. 3)

We proceed to proof the effectiveness of operations defined above by testing point D:

1) D(x,y) = (-1, 4) Given.

2) (x',y') = (1,4) By (Eq. 1)

3) (x'',y'') = (1, 1) By (Eq. 2)

4) D'(x,y) = (-3,1) By (Eq. 3)/Result

7 0
3 years ago
Based on the scale drawing, what is the length, in feet, of the actual parking lot? On the drawing they have the width 12.8 cm a
aleksandrvk [35]

Answer:

The width of 48 feet is represented by 12.8cm; the length represented by 1cm is 48/12.8 = 15/4 = 3.75 feet.

The length on the drawing is 3.2cm, which is exactly 1/4 of the width of 12.8cm; therefore the length of the actual parking lot is 48/4 = 12 feet.

5 0
4 years ago
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