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3 years ago

HELP MEEEEE PLZZZZZZZZZZZZZZZZZZZZZZZZ

Mathematics

2 answers:

valina [46]3 years ago

5 0

The third graph. He stops twice, once at the stop sign and again when he reached his destination. on the graph this would be represented with the line at zero which means it can't be the first graph. since it says that he started at a constant speed that means the line doesn't start at zero (since zero indicates no movement and a diagonal line indicates acceleration and he did not accelerate to that speed he started at that speed) and the only other graph that doesn't start at zero is the third graph. This graph follows the journey described as it goes to zero for when he stopped at the stop sign and then accelerates up to the constant speed (the horizontal line) and the decelerates to a stop when he reached work (at the zero).

Semmy [17]3 years ago

3 0

3rd graph is the correct answer

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In triangle ABC angle A=45 angle B =40 and a=7.Which equation should you solve to find b?

coldgirl [10]

We have been given that in triangle ABC angle A=45 angle B =40 and a=7. We are asked to find the equation that we can use to solve for 'f'.

We have two angles and opposite sides to these angles.

We will use Law of Sines to solve our given problem.

$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}$ , where a, b and c are opposite sides corresponding to angles A, B, and C respectively.

The angle opposite to side b is 40 degrees and angle opposite to side a is 45 degrees.

Upon substituting these values in Law of Sines, we will get:

$\frac{7}{\sin(45^{\circ})}=\frac{b}{\sin(40^{\circ})}$

Therefore, our required equation would be $\frac{7}{\sin(45^{\circ})}=\frac{b}{\sin(40^{\circ})}$ .

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4 years ago

What two partial products would you add to find 513 x 46

Afina-wow [57]

First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

  513
x46
--------------------------
  18 (as 6*3 = 18)
  60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
  120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
  400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)

Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.

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Step-by-step explanation:

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