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Nikitich [7]
4 years ago
8

How many vertices does the preimage have

Mathematics
1 answer:
PtichkaEL [24]4 years ago
3 0
Maybe 3 or 4 depends how many orientations they had.
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16% of what number is 17?
kirill [66]
To find a percentage of a number, convert the percent to a decimal, then multiply the number by it. In this case, 16% = 0.16.

N * 0.16 = 17
N = 106.25
(thanks to Vanessa033 for catching my mistake; I owe you one)
3 0
3 years ago
Read 2 more answers
Hey! please help i’ll give brainliest
Dvinal [7]

Answer:

B. is the answer

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\
-----------------------------\\\\
\textit{area of a circle}\\\\
A=\pi r^2\qquad r=radius\\\\
\textit{area of half a circle}\\\\
A=\cfrac{\pi r^2}{2}\\\\
-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}
\\\\\\

\begin{array}{clclll}
\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\
\uparrow &&\uparrow \\
triangle's&&semi-circle's
\end{array}\impliedby \textit{area of shaded area}\\\\
-----------------------------\\\\
\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
3 years ago
Read 2 more answers
Hey, if anyone could h3lp me with this it would b gr8 !!
Viefleur [7K]

Step-by-step explanation:

AB=OB-OA

AB=[4,-2]-[-4,6]

AB=[8,-8],|AB|=8units

BC=OC-OB

BC=[-6,-4]-[4,-2]

BC=[-10,-2],|BC|=√104

AC=OC-OA

AC=[-6,-4]-[-4,6]

AC=[-2,-10],|AC|=√104

d. Based on the lengths of the sides,the triangle is isosceles

5 0
3 years ago
I’m so confused and neeeed help
AnnyKZ [126]

Answer:

Perimeter = √40 + 6 + 4√2 + √28

Step-by-step explanation:

As we know that the perimeter of a triangle is the sum of the length of sides.

<em>Perimeter =  4√2 + x + 6 + y</em>

Now for x and y-

<u>I. By Pythagorean theorem in left side right angle triangle-</u>

( 4√2)² = 2² + x²

32 - 4 = x²

x² = 28

x = √28

<u>II. By Pythagorean theorem in Right angle triangle-</u>

y² = 2² + 6²

y² = 4 + 36

y² = 40

y = √40

Hence Perimeter =  4√2 + x + 6 + y

P = 4√2 + √28 + 6 + √40

∴ P = √40 + 6 + 4√2 + √28

7 0
3 years ago
Read 2 more answers
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