Answer:
the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Step-by-step explanation:
Given the data in the question;
μ_x = 10 pound bags
standard deviation s_x = 0.24 pounds
sample size n = 4
The bag weights are normally distributed so;
p( x' less than 9.8 ) will be;
p( (x'-μ_x' / s_x') < (9.8-μ_x' / s_x') )
we know that;
μ_x' = μ_x = 10
and s_x' = s_x/√n = 0.24/√4
so; we substitute
p( z < ( (9.8 - 10) / (0.24/√4) )
p( z < -0.2 / 0.12 )
p( z < -1.67 )
{ From z-table }
⇒ p( z < -1.67 ) = 0.0475 ≈ 0.05
Therefore, the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
B I’m pretty sure I think or 826
Answer:
a) 51.4
b) answer attached
c) 48.59% female
Step-by-step explanation:
a) Male driver = 100-48.6 = 51.4%
b) answer attached below
c) probability that out of 20-64 group a randomly selected sample is female
( 39.54 ÷ 81.36 ) x 100
= 48.59% chance of her being a female
Y=-7x-5
9=-7(-2)-5
9=14-5
9=9
Please mark the brainliest, if you think i helped!
Answer:
The anwser to your question would be negative 23 (-23)
