To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer:
3
Step-by-step explanation:
-6 x 3 = -9
F(x) = 2(x-3) + 4
F(-2) = 2(-2-3) + 4
F(-2) = 2(-5) + 4
F(-2) = -10 + 4
F(-2) = -6
Hope this helps
Answer:
x ≤ -5
Step-by-step explanation:
According to given condition:
3x + 17 ≤ 2(1 - x)
By simplifying:
3x + 17 ≤ 2 - 2x
Adding 2x - 17 on both sides we get:
3x + 2x ≤ 2 - 17
5x ≤ - 15
Dividing both sides by 5 we get:
x ≤ -5
i hope it will help you!
Answer:
for both of the them the range geografeclly is 1 up
