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Natasha2012 [34]

3 years ago

7

How comes proofs are so hard

1 answer:

Mama L [17]3 years ago

8 0

They get easier once you keep doing them, It took me a little while to learn.

Do you have a exact question? I can help you

You might be interested in

What is the slope of (2,22) -(4,32)<br><br>a.5<br>b.10<br>c.2<br>d.1

zhenek [66]

Use the formula for the slope of a line by substituting the given coordinates:
$\frac{ y_{2}-y_{1}}{ x_{2} - x_{1} }$
So for the coordinates (2,22) and (-4,-32)
So (-32-22)/(-4-2)= -54/-6= 9 is the slope of the line

6 0

3 years ago

1.give the sequence 8.5.2.-1,...at what term will the number become -25? A.11th term B.10th term C.12th term D.20th term 2.which

Nitella [24]

Answer: 1. C(12) 2. B(n-1-14) 3. A(30)

Step-by-step explanation: For number one the nth term with common difference d and first term a is a+(n-1)d=nth term, plug in the values you have and solve for n to get 12. For number 2 an algebraic expression has a variable and a constant but doesn't have an equal sign. So it is B. For number three just add them up. Hope this helped!

6 0

3 years ago

PLEASE ANSWER !!

ANEK [815]

Answer:

Check the explanation.

Step-by-step explanation:

As the graph of a linear function f passes through the point (-2,-10) and has a slope of 5/2.

As the slop-intercept form is given by:

$y = mx+b$

where m is the slope and b is the y-intercept.

substituting the values (-2, -10) and m = 5/2 in the slop-intercept form to determine y-intercept.

$y = mx+b$

$-10=\frac{5}{2}\left(-2\right)+b$

$-\frac{5}{2}\cdot \:2+b=-10$

$-5+b=-10$

$-5+b+5=-10+5$

$b=-5$

And the equation of the line in the slope-intercept form will be:

$y = mx+b$

putting b = -5 and slope = m = 5/2

$y = mx+b$

$y=\frac{5}{2}x+\left(-5\right)$

$y=\frac{5}{2}x-5$

Determining the zero of function.

As we know that the real zero of a function is the x‐intercept(s) of the graph of the function.

so let us determine the value of x (zero of function) by setting y = 0.

$0=\frac{5}{2}x-5$

$\frac{5}{2}x-5=0$

$\frac{5}{2}x=5$

$5x=10$

$x=2$

Therefore, the zeros of the function will be:

x = 2

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%20x%2B2" id="TexFormula1" title="f(x)=\sqrt x+2" alt="f(x)=\sqrt x+2" align

Andrew [12]

Answer:

$(x-2)^2$

Step-by-step explanation:

To find the inverse of this function, you need to replace the location of the x and the y.

You start with $y=\sqrt{x}+2$ . Now, replace the x and the y, and try to isolate the y.

$x=\sqrt{y}+2\\x-2=\sqrt{y}\\y=(x-2)^2$

Hope this helps!

8 0

3 years ago

Find the value of f(-3) and g(3) if f(x) = -6x + 3 and g(x) = 3x + 21r.

tekilochka [14]

Answer:

Part 1) $f(-3)=21$

Part 2) $g(3)=9+21r$

Step-by-step explanation:

Part 1) Find the value of f(-3)

we have

$f(x)=-6x+3$

we know that

f(-3) is the value of the function f(x) for x=-3

so

substitute the value of x=-3 in the function to find f(-3)

$f(-3)=-6(-3)+3$

$f(-3)=18+3$

$f(-3)=21$

Part 2) Find the value of g(3)

we have

$g(x)=3x+21r$

we know that

g(3) is the value of the function g(x) for x=3

so

substitute the value of x=3 in the function to find g(3)

$g(3)=3(3)+21r$

$g(3)=9+21r$

6 0

3 years ago