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raketka [301]
3 years ago
7

PLZ HELP!!!! WILL MARK BRAINLEST IF CORRECT

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Answer: the answer is 54

Step-by-step explanation: The error in the expression was that it was multiplied by 1 so it can't be one unless it was also 1 and it's not it is 54.

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Alex has 7 pizzas he wants to share equally with 10 friends. How much pizza will each friend receive?
Norma-Jean [14]
Each friend will receive 1 or half a slice
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The number +10 can be used to indicate a
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The number + 10 can be used to indicate a  : 
10 degree rise in temperature.

Temperature can be measured in Kelvin , Celsius, and Fahrenheit. In all measurement, + number indicate a rise in the temperature
4 0
3 years ago
'If there is a ton of corn in a tank, and 500 pounds of corn are removed, what is the
Roman55 [17]

Answer:

1,500 pounds :>

Step-by-step explanation:

There are 2,000 pounds in 1 ton, take away 500 from 2,000 you get 1,500

4 0
3 years ago
Uestion to Answer:<br> 1. What can you say about the value of a polynomial<br> when P(a)=0
Vlad [161]

Answer:

The expression indicates that when polynomial P(x) is divided by divisor x - a, the remainder of the division is 0

Step-by-step explanation:

<em>The question would be better answered if you gave option. Since there is no option, I'll answer the question generally.</em>

<em></em>

Given

P(a) = 0

The above expression indicates that when polynomial P(x) is divided by divisor x - a, the remainder of the division is 0

Take for instance, the polynomial is:

P(x) = x^2 - x - 2

And the divisor is x - 2, then P(2) = 0 because (x - 2) is a divisor of the equation.

\frac{P(x)}{x} =\frac{x^2 - x - 2}{x - 2}

Factorize the numerator

\frac{P(x)}{x} =\frac{(x- 2)(x + 1)}{x - 2}

\frac{P(x)}{x} =x + 1}

See that x - 2 is a divisor

To check

Set x - 2 to 0

x -2 = 0

x = 2

So, we have:

P(x) = x^2 - x - 2

P(2) = 2^2 - 2 - 2

P(2) = 4 - 2 - 2

P(2) = 0

8 0
3 years ago
Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from th
fredd [130]

Using continuity concepts, the answers are given by:

  • The function is right-continuous at x = 0.
  • The function is left-continuous at x = 1.

------------------------------------

A function f(x) is continuous at x = a if:

\lim_{x \rightarrow a^{-}} f(x) = \lim_{x \rightarrow a^{+}} f(x) = f(a)

  • If \lim_{x \rightarrow a^{-}} f(x) = f(a), the function is left-continuous.
  • If \lim_{x \rightarrow a^{+}} f(x) = f(a), the function is right-continuous.
  • For the given function, the continuity is tested at the points in which the definitions are changed, x = 0 and x = 1.

------------------------------------

At x = 0.

  • Approaching from the left, it is less than 0, thus:

\lim_{x \rightarrow 0^-} f(x) = \lim_{x \rightarrow 0} x + 9 = 0 + 9 = 9

  • Approaching from the right, it is more than 0, thus:

\lim_{x \rightarrow 0^+} f(x) = \lim_{x \rightarrow 0} e^x = e^0 = 1

  • The numeric value is:

f(x) = e^0 = 1

  • Since [tex]\lim_{x \rightarrow 0^+} f(x) = f(0), the function is right-continuous at x = 0.

------------------------------------

At x = 1.

\lim_{x \rightarrow 1^-} f(x) = \lim_{x \rightarrow 1} e^x = e^1 = e

\lim_{x \rightarrow 1^+} f(x) = \lim_{x \rightarrow 1} 4 - x = 4 - x = 3

f(1) = e^1 = e

  • Since [tex]\lim_{x \rightarrow 1^-} f(x) = f(1), the function is left-continuous at x = 0.

A similar problem is given at brainly.com/question/21447009

7 0
3 years ago
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