THE ANSWER IS: D. y=-3x+11
when two lines are parallel, they share the same slope, which is -3
then plug in the given point into slope intercept form then solve for standard form
Answer:
C
Step-by-step explanation:
Melania: 2 1/5 = 11/5
Cathy 1 3/4 as far as Melania did => 7/4 x 11/ 5 = 77 / 20 = 3 17/20
Convert each mixed number to an improper fraction
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Convert 6&1/2 to an improper fraction
6&1/2 = (6*2+1)/2
6&1/2 = (12+1)/2
6&1/2 = 13/2
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Do the same for 9&1/4
9&1/4 = (9*4+1)/4
9&1/4 = (36+1)/4
9&1/4 = 37/4
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Now multiply the improper fractions 13/2 and 37/4. Multiply straight across
(13/2)*(37/4) = (13*37)/(2*4)
(13/2)*(37/4) = 481/8
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The last step is to use long division to find the mixed number equivalent of 481/8
Or we an say
60*8 = 480
So 60*8+1 = 480+1
which means
481/8 = (480+1)/8 = 480/8+1/8 = 60&1/8
Making the final answer to be choice C
Another way to get the answer is to convert 481/8 into a decimal to get 60.125 and then convert that back to a mixed number. You should get 60&1/8
<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
<span>(1−sin2(x))/(sin(x)−csc(x))<span>
</span>sin2x+cos2x=1</span>
<span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span>
<span>csc(x)=1/sin(x)</span>
<span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span>
<span>sin2(x)− 1=-cos2(x)</span>
<span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>
the answer is the letter a)
-sin x
</span><span>
5. Find all solutions in the interval [0, 2π). (6 points)sin2x + sin x = 0</span> using a graphical tool
the solutions
x1=0
x2=pi
<span>x3=3pi/2
the answer is the letter </span><span>
D) x = 0, π, three pi divided by two</span>
Answer:
3
Step-by-step explanation:
A mandatory relationship means that for every A there must be a B and vice versa. The excessive is saying that you have a relationship with 3 records each, therefore the bridge relation cannot have less than 3 records otherwise the mandatory aspect will be broke.
I hope you find this information useful and interetsing! Good luck!
