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Bas_tet [7]
3 years ago
10

Solve the following system of equations. Express your answer as an ordered pair in the format (a,

Mathematics
2 answers:
choli [55]3 years ago
8 0
The second equation is <span>-5-2y=2, then
</span>
<span>-2y=2-(-5),
</span>
-2y=2+5,
-2y=7,
y=7÷(-2),
y=-3.5.
The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then
2x+5·(-3.5)=16,
2x-17.5=16,
2x=16-(-17.5),
2x=16+17.5,
2x=33.5,
x=33.5÷2,
x=16.75.
Answer: (16.75,-3.5)


aleksandr82 [10.1K]3 years ago
3 0

Answer:

(x,y) = (-2,4)

Step-by-step explanation:

Consider the system of equation,

2x + 5y = 16  .......... (1)

-5x - 2y = 2   ......... (2)

Using Elimination method to solve the system of equation,

Multiply equation (1) by 5 , we get,

10x + 25y = 80  ...........(3)

Multiply equation (2) by 2 , we get,

-10x - 4y = 4   ......... (4)

Adding (3) and (4) , we get,

10x + 25y +( -10x - 4y )= 4 + 80

10x and -10x got cancel, we get,

25y  - 4y = 84

⇒ 21y = 84

⇒ y = 4

Put y = 4 in (1),

2x + 5(4) = 16 ⇒ 2x  = 16 - 20 ⇒ 2x  = -4 ⇒ x  = -2

Thus, (x,y) = (-2,4)


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\sf Hello!

• \sf AB = x + 6
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• \sf AC = 36 - x

\sf We're \:given\: that \:A,\: B\: and \:C \:are \:Collinear\: points

\sf Then,

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⇒ \sf x + 6 + 3x - 5 = 36 - x

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3 years ago
Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block
marusya05 [52]

Answer:

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i think

Stepkby-step explanation:

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4 0
2 years ago
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Will give brainliest please help <br><br>4b + 7b +5 <br><br>i need help simplifying.​
vitfil [10]

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Solve for a. 1/3(21-3a)=6-a
OverLord2011 [107]

Answer:

no solution

Step-by-step explanation:

Given

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The sum of three numbers is 10. Two times the second number minus the first number is equal to 12.
eimsori [14]

<u>Answer:</u>

-10,1,19

<u>Step-by-step explanation:</u>

<u></u>

x+y+z = 10 (Equation 1)

2y-x= 12  (Equation 2)

x-y+2z = 7 (Equation 3)

(Equation 2): -x = -2y+12

                       x = 2y-12 (Equation 4)

(Equation 1) - (Equation 3): 2y-z = 3

                                              -z = -2y+3

                                               z = 2y-3 (Equation 5)

Substitute (4) and (5) into (1)

x+y+z = 10

(2y-12)+y+(2y-3) = 10

5y-15 = 10

5y = 5

y=1

Substitute y=1 into (2)

2y-x= 12

2(1)-x= 12

2-x= 12

-x= 12-2

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Substitute y=1 and x=-10 into (1)

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z-9 = 10

z = 10+9

z = 19

Order: x = -10, y = 1, and z = 19

8 0
3 years ago
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