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evablogger [386]
3 years ago
6

What is the solution to 8x - 3(2x - 4) = 3(x - 6)?

Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

X=+30 that's all I know, Sorry I couldn't help much :(

You might be interested in
Find the indefinite integral ∫((x^2)/(4x^3+9)) dx
Leya [2.2K]

Answer:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)  +  \rm C

Step-by-step explanation:

we would like to integrate the following indefinite integral:

\displaystyle \int  \frac{ {x}^{2} }{4 {x}^{3}  + 9} dx

in order to integrate it we can consider using u-substitution also known as the reverse chain rule and integration by substitution as well

we know that we can use u-substitution if the integral is in the following form

\displaystyle \int f(g(x))g'(x)dx

since our Integral is very close to the form we can use it

let our u and du be 4x³+9 and 12x²dx so that we can transform the Integral

as we don't have 12x² we need a little bit rearrangement

multiply both Integral and integrand by 1/12 and 12:

\displaystyle  \frac{1}{12} \int  \frac{ 12{x}^{2} }{4 {x}^{3}  + 9} dx

apply substitution:

\displaystyle  \frac{1}{12} \int  \frac{ 1}{u} du

recall Integration rule:

\displaystyle  \frac{1}{12}   \ln(|u|)

back-substitute:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)

finally we of course have to add constant of integration:

\displaystyle  \frac{1}{12}   \ln( |{4x}^{ 3}  + 9|)  +  \rm C

and we are done!

6 0
3 years ago
Malik wrote 18 ➗6 = 3. Which problem can he solve using this equation?
ki77a [65]

Answer: Anything for example:

Malik has 6 friend, he wants to equally give them some of the 18 cookies he back earlier that morning. How much will he give each person?

Step-by-step explanation: And the answer will be 3

6 0
3 years ago
Read 2 more answers
A coffee shop collected the following information regarding purchases from 110 of its customers 59 purchased coffee 39 purchased
Andrej [43]

Answer:

Let X be the number of customer purchased coffee

Let Y be the number of customer purchased donuts

Then X\cap Y is the number of customer purchased both coffee and donuts

X\cup Y  is the number of customer purchased both coffee or donuts

<em><u>The Number of customers purchased  only Coffee:</u></em>

Number of customers purchased  only donuts =n(X -Y)

n( X -Y) = n(X) - n(X \cap Y)

n(X-Y) = 59 -16

n(Y - X) = 43

<em><u>The Number of customers purchased  only donuts:</u></em>

Number of customers purchased  only donuts =n(Y -X)

n(Y - X) = n(Y) - n(X \cap Y)

n(Y - X) = 39 -16

n(Y - X) = 23

<u>The Number of customers did not purchase either of these items:</u>

Number of customers did not purchase either of these items = n(X\cup Y)^{\prime}

First lets find   n(X\cup Y)

n(X\cup Y) = n(X) +  n(Y) - n( X \cap Y)

n(X\cup Y) = 59 + 39 - 16

n(X\cup Y)  = 82

n(X\cup Y)^{\prime}  =110 -  n(X\cup Y)  = 28

5 0
4 years ago
A bookstore has a sale:
ira [324]
16.00 I think by 40% for one book but for two is 80%
7 0
4 years ago
Homework problem #7: 24567389+35432611=what there is soo much regrouping, could someone show me how to do it?
Natasha_Volkova [10]

Answer:

24567389+35432611 =60000000

Step-by-step explanation:

Given

24567389+35432611 =

Required

Solve

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

<em>The numbers in parentheses are carried from previous sum</em>

Start from the right

9 + 1 = 10 \to Write 0, carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                         0

8 + 1 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                       0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                   0 0 0

7+2 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

                0 0 0 0

6 +3 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

             0  0 0 0 0

5 +4 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

         0  0  0 0 0 0

4 +5 + (1) = 10 \to Write 0 carry 1

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

      0  0  0  0 0 0 0

2 +3 + (1) = 6 \to Write 6

  2 4 5 6 7 3 8 9

+ 3 5 4 3 2 6 1 1

----------------------------

 6  0  0  0  0 0 0 0

Hence:

24567389+35432611 =6  0  0  0  0 0 0 0

8 0
3 years ago
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